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slavikrds [6]
3 years ago
11

The graph of y = 2 is shifted down by 6 units and to the left by 9 units.

Mathematics
1 answer:
luda_lava [24]3 years ago
7 0

Answer:

(-9, -4)

Step-by-step explanation:

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Can someone help me with this question in so confused
Svetlanka [38]

Answer:

D(1, 2) → D'(2, 7)

E(-3, -5) → E'(-10, 0)

F(4, -1) → F'(11, 4)

Step-by-step explanation:

D(1, 2) → D'   ________

Translate image (3x - 1, y + 5)

(1, 2), x = 1 and y = 2

3x - 1 = 3(1) - 1 = 3 - 1 = 2

y + 5 = (2) + 5 = 7

E(-3, -5) → E' ________

(-3, -5), x = -3 and y = -5

3x - 1 = 3(-3) - 1 = -9 - 1 = -10

y + 5 = (-5) + 5 = 0

F(4, -1) → F'   ________

(4, -1), x = 4 and y = -1

3x - 1 = 3(4) - 1 = 12 - 1 = 11

y + 5 = (-1) + 5 = 4

3 0
1 year ago
Factor z^2 – 3z – 18. A. (z + 3)(z – 6) B. (z – 3)(z – 6) C. (z + 8)(z – 10) D. (z + 2)(z – 9)
ozzi
Work shown above! Answer would be A!

5 0
3 years ago
The speed of the current in a creek is 5 mph. A person clan kayak 3 mi upstream in the same time that it takes him to kayak 13 m
Brut [27]

Answer:

8

Step-by-step explanation:

0) the basic formula is: L=v*t, where L - distance, v - speed/velocity; t - time;

1) if the person's speed in still water is 'v' and the speed of water is 5 (according to the condition), then the upstream speed is 'v-5' and the downstream speed is 'v+5';

2) according to the condition the upstream time and the downstream time are the same, it means t₁=t₂=t, where t₁=upstream time and t₂=downstream time;

3) according to the items above it is possible to make up the equation of the upstream travel: t(v-5)=3; ⇒ t=3/(v-5);

4) according to the items above it is possible to make up the equation of the downstream travel: t(v+5)=13; ⇒ t=13/(v+5);

5) if t=3/(v-5) and t=13/(v+5), then

\frac{3}{v-5} =\frac{13}{v+5}; \ => \ v=8.

8 0
2 years ago
Please please help please ASAP
Vedmedyk [2.9K]

Answer:

VT = 50√3 , PT = 50

Step-by-step explanation:

Given

PV = 100

With reference angle 60°

hypotenuse (h) = 100

perpendicular (p) = ?

Now

Sin 60° = p/h

√3 / 2 = p / 100

p = √3 * 100 / 2

p = 50√3

Also

With reference angle 30°

hypotenuse (h) = 100

perpendicular (p) = ?

sin 30° = p/h

1/2 = p / 100

p = 100 / 2

p = 50

Hope it will help :)

8 0
3 years ago
Please help me on this quick!! Thanks and please show work.
FinnZ [79.3K]
The two parallel bases b1 and b2 are
b1 = 12
b2 = 9
the order of which base you pick doesn't matter

The height is h = 10 and it's perpendicular to each base.

The area is...

A = (1/2)*h*(b1+b2)
A = (1/2)*10*(12+9)
A = (1/2)*10*(21)
A = 5*21
A = 105

Final Answer: B) 105 square centimeters
8 0
3 years ago
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