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3 years ago

What kinds of places may hold life ?

1 answer:

7 0

The planets that could host liquid water and might have rocky ... Liquid water is a necessity for the kind of life we know

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Assume that a point mutation changes the codon AUU to AUC. Why is this a neutral mutation

lukranit [14]

I used the genetic code table. mRNA codon ===> amino acid

1st base 2nd base 3rd base
A U U ===> Isoleucine
A U C ===> Isoleucine

The point mutation of codon AUU to AUC is a neutral mutation because it neither benefits nor deter the ability of the organism to survive and reproduce.

As you can see, Both codons result to the Isoleucine amino acid.

Another codon that will still result to the Isoleucin amino acid is AUA.

3 0

3 years ago

Group the following electron configurations in pairs that would represent similar chemical properties at their atoms;

marishachu [46]

<u>Answer:</u> Pairs are: (a) and (d), (b) and (f), (c) and (e)

<u>Explanation:</u>

In a periodic table, elements are arranged in 18 vertical columns known as groups and 7 horizontal rows known as periods.

Elements arranged in a group show similar chemical properties because of the presence of same number of valence electrons.

Valence electrons are defined as the electrons which are present in the outermost shell of an atom. Outermost shell has the highest value of 'n' that is principal quantum number.

For the given options:

<u>For a:</u>

The given electronic configuration is: $1s^22s^22p^63s^2$

The number of valence electrons in the given configuration are 2

<u>For b:</u>

The given electronic configuration is: $1s^22s^22p^63s^3$

The number of valence electrons in the given configuration are [2 + 3] = 5

<u>For c:</u>

The given electronic configuration is: $1s^22s^22p^63s^23p^64s^23d^{10}4p^6$

The number of valence electrons in the given configuration are [2 + 6] = 8

<u>For d:</u>

The given electronic configuration is: $1s^22s^2$

The number of valence electrons in the given configuration are 2

<u>For e:</u>

The given electronic configuration is: $1s^22s^22p^6$

The number of valence electrons in the given configuration are [2 + 6] = 8

<u>For f:</u>

The given electronic configuration is: $1s^22s^22p^63s^23p^3$

The number of valence electrons in the given configuration are [2 + 3] = 5

Electronic configuration of (a) and (d) will form a pair, (b) and (f) will form a pair, (c) and (e) will form a pair and will have similar chemical properties.

Hence, the pairs are: (a) and (d), (b) and (f), (c) and (e)

4 0

3 years ago

What is the main difference between electron configuration and orbital notation?

8_murik_8 [283]

Answer:

Orbital Notation is more specific on where exactly the electron is placed.

Explanation:

When writing an electron configuration for an atom, rather than writing out the occupation of each and every orbital specifically, you instead lump all the core electrons together and designate it with a symbol of the corresponding noble gas on the Periodic Table.

the arrangement of electrons in the orbitals of an atom or molecule

While Orbital Notation is a visual transformation of the electron configuration. It shows you where each specific electron is placed and what its "spin" is.

Glad I could help!

6 0

3 years ago

A gas occupies a volume of 50.0 mL at 100K and 630 mmHg. At what temperature would

rodikova [14]

PV / T = P'V' / T'

V = V'

P / T = P' / T'

P = 630 mmHg
T = 100 K
P' = 1760 mmHg
T' = ?

630 / 100 = 1760 / T'

T' = 1760 / 6,3

T' = 279,36 K

T' ≈ 280 K

3 0

2 years ago

A container of gas has a volume of 3.5 L and a pressure of 0.8 atm. Assuming the temperature remains constant, what volume of ga

vovikov84 [41]

<h3>Answer:</h3>

5.6 L

<h3>Explanation:</h3>

We are given;

Initial volume, V1 = 3.5 L
Initial pressure, P1 = 0.8 atm
Final pressure, P2 = 0.5 atm

We are required to calculate the final volume;

According to Boyle's law, the volume of a fixed mass of a gas and the pressure are inversely proportional at a constant temperature.

That is; P α 1/V
Mathematically, P=k/V
At two different pressure and volume;

P1V1 = P2V2

In this case;

Rearranging the formula;

V2 = P1V1 ÷ P2

= (0.8 atm × 3.5 L) ÷ 0.5 atm

= 5.6 L

Therefore, the resulting volume is 5.6 L

7 0

3 years ago