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Feliz [49]
2 years ago
9

A compound is made of 49.31% C, 43.79% 0 and the rest hydrogen. The molar

Chemistry
1 answer:
Alexeev081 [22]2 years ago
8 0

Explanation:

49.31 + 43.79 = 93.10

finding the percentage of hydrogen in the compound hence 100-93.10 =6.9

therefore 6.9 percent of hydrogen is present in the compound

assuming that the compound is in 100 g so the elements present would be 49.31g of C , 43.79g of O and 6.9g of H

no. of moles of C = given mass÷molar mass

= 49.31 ÷ 12

=<em><u>4</u></em><em><u>.</u></em><em><u>1</u></em><em><u>1</u></em><em><u> </u></em><em><u>m</u></em><em><u>o</u></em><em><u>l</u></em>

no of moles of O = givem mass ÷molar mass

=43.79÷ 16

=<em><u>2</u></em><em><u>.</u></em><em><u>7</u></em><em><u>3</u></em><em><u> </u></em><em><u>m</u></em><em><u>o</u></em><em><u>l</u></em>

no. of moles of H =6.9÷1

=<em><u>6</u></em><em><u>.</u></em><em><u>9</u></em><em><u> </u></em><em><u>m</u></em><em><u>o</u></em><em><u>l</u></em>

dividing the no. of moles of each element by the least count of the elemnt to get the ratio of the simple whole numbr

therefore

so by dividing we get 1:1:2 of C:O:H

the empirical formula is CH2O

empirical formula mass of CH2O IS

= (12)+(2×1)+(16)

= 12+2+16

=30 G/MOL

n= molar mass of the compound ÷ empirical formula mass of the compound

so, n= 146.1 ÷30

n=5

molecular formula = n×empirical formula

<em>m</em><em>o</em><em>l</em><em>e</em><em>c</em><em>u</em><em>l</em><em>a</em><em>r</em><em> </em><em>f</em><em>o</em><em>r</em><em>m</em><em>u</em><em>l</em><em>a</em><em>=</em><em> </em><em>5</em><em>×</em><em>C</em><em>H</em><em>2</em><em>O</em>

<em>m</em><em>o</em><em>l</em><em>e</em><em>c</em><em>u</em><em>l</em><em>a</em><em>r</em><em> </em><em>f</em><em>o</em><em>r</em><em>m</em><em>u</em><em>l</em><em>a</em><em>=</em><em>C</em><em>5</em><em>H</em><em>1</em><em>0</em><em>O</em><em>5</em><em> </em><em>(</em><em>r</em><em>i</em><em>b</em><em>o</em><em>s</em><em>e</em><em> </em><em>i</em><em>s</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>c</em><em>o</em><em>m</em><em>p</em><em>o</em><em>u</em><em>n</em><em>d</em><em>)</em>

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