Answer:
Number of fish in 2006 = 845 fishes (Approx.)
Step-by-step explanation:
Given;
Number of fish in 2000 = 1,150 fishes
Decreasing rate = 5% per year
Find:
Number of fish in 2006
Computation:
Exponential decay function:
F = P[1-r]ⁿ
Number of year = 2006 - 2000
Number of year = 6 year
Number of fish in 2006 = 1,150[1-5%]⁶
Number of fish in 2006 = 1,150[1-0.05]⁶
Number of fish in 2006 = 1,150[0.95]⁶
Number of fish in 2006 = 1,150[0.735]
Number of fish in 2006 = 845.25
Number of fish in 2006 = 845 fishes (Approx.)
Answer:
38
Step-by-step explanation:
Given that,
x = -4
f(x)=x² - 4x +6
so,
f(-4)= (-4)² - 4 . (-4) +6
=16 +16 +6
= 38
Answer:
Step-by-step explanation:
If the area of a triangle is 150cm^2, the formula would look like:
150=0.5b*h
So, if we were to solve for the base in terms of h, we'd simply divide both sides by 0.5b getting:
(150)/(0.5b)=h
which simplifies to
h=300b
