$(\stackrel{x_1}{\frac{5}{6}}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-3}(x-\stackrel{x_1}{\frac{5}{6}})$

8 0

2 years ago

I know he is incorrect but I just can’t say why please help

egoroff_w [7]

Answer:

Step-by-step explanation:

Umm, Wheres Tanner's graph? Please post it so that I could answer your question!! :)

3 0

3 years ago

What is the charge on an object that has 1. 25 * 10 ^-17.

Aliun [14]

Answer: To determine the charge on an object, determine the number of excess protons or excess electrons. Multiply the excess by the charge of an electron or the charge of a proton - 1.6 x 10-19 C.

Step-by-step explanation:

7 0

2 years ago

X -1 < -4<br><br> What is ittttttttt

Kamila [148]

Answer:

x<-3

Step-by-step explanation:

x-1+1<-4+1

x<-3

8 0

3 years ago