Question

Which are the solutions of the quadratic equation? x2 = 7x + 4 –7, 0 7, 0

Answer 1

Answer:

$x=\frac{7+\sqrt{65}}{2}, x=\frac{7-\sqrt{65}}{2}$

Step-by-step explanation:

We are given that a quadratic equation

$x^2=7x+4$

$x^2-7x-4=0$

We have to find the solutions of the quadratic equation.

a=1, b=-7,v=-4

Quadratic formula:$x=\frac{-b\pm\sqrt{b^2-4ac}{2a}$

Substitute the values in the quadratic formula

$x=\frac{-(-7)\pm\sqrt{(-7)^2-4(1)(-4)}}{2(1)}$

$x=\frac{7\pm\sqrt{49+16}}{2}$

$x=\frac{7\pm\sqrt{65}}{2}$

$x=\frac{7+\sqrt{65}}{2}, x=\frac{7-\sqrt{65}}{2}$

Hence, the solutions of quadratic equation are

$x=\frac{7+\sqrt{65}}{2}, x=\frac{7-\sqrt{65}}{2}$

Answer 2

1) Equation: x^2 = 7x

2) Transpose terms: x^2 - 7x = 0

3) Factor: x (x - 7) = 0

4) Solutions: x = 0 and x - 7 = 0 => x =0 and x = 7.

Answer: 0 and 7