Answer : The percent by volume of oxygen gas in the mixture is, 5.3 %
Explanation :
According to the Raoult's law,
where,
= total partial pressure of solution = 3.8 atm
= partial pressure of oxygen = 0.20 atm
= mole fraction of oxygen = ?
Now put all the given values in this formula, we get:
Now we have to calculate the percent by volume of oxygen gas in the mixture.
The mole percent of oxygen gas =
As we know that, there is a direct relation between the volume of moles.
So, mole percent of oxygen gas = volume percent of oxygen gas
Volume percent of oxygen gas =
Therefore, the percent by volume of oxygen gas in the mixture is, 5.3 %