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Korolek [52]
3 years ago
12

When two H atoms are brought together from large distances they can make H2. As the bond begins to form, the force between the a

toms becomes more (attractive, repulsive) and the potential energy
a) increases,
b) stays the same,
c) decreases
Chemistry
1 answer:
labwork [276]3 years ago
7 0

Answer: Option (a) is the correct answer.

Explanation:

As potential energy is the energy obtained by a substance or object due to its position.

So, when a chemical bond is formed between energy is located at a particular position due to which there exists a chemical potential energy.

Therefore, as the bond begins to form, the force between the atoms becomes more (attractive, repulsive) which means the bond reaches to a higher position.

Hence, there will be an increase in potential energy.

Thus, we can conclude that as the bond begins to form, the force between the atoms becomes more (attractive, repulsive) and the potential energy increases.

You might be interested in
+
aleksklad [387]

Answer:

<h3>The answer is 41.05 %</h3>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual density = 0.95 g/mL

error = 0.95 - 0.56 = 0.39

So we have

p(\%) =  \frac{0.39}{0.95}  \times 100 \\  = 41.0526315...

We have the final answer as

<h3>41.05 %</h3>

Hope this helps you

4 0
4 years ago
I am a metal that has 3 valence electrons and 123 neutrons
zlopas [31]

Answer:

The answer is Boron

Explanation:

3 0
3 years ago
A sample of Br2 gas has a volume of 29.0L and a pressure of 1.50 atm. If the initial temperature of the gas is 23 °C, what volum
Jobisdone [24]

Answer:

V₂ = 22.84 L

Explanation:

Given data:

Initial volume = 20.0 L

Initial pressure = 1.50 atm

Initial temperature = 23 °C (23 +273 = 296 K)

Final temperature = 271°C (271+273 = 544 K)

Final pressure = 3.50 atm

Final volume = ?

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1.50 atm × 29.0L ×544 K / 296 K × 3.50 atm

V₂ = 23664 atm .L. K / 1036 atm.K

V₂ = 22.84 L

5 0
3 years ago
Determine the volume (in liters) of a 87.8-9 sample of OF2 gas at 307 torr and 264°C.
expeople1 [14]

Answer:

V = 177.4 L.

Explanation:

Hello there!

In this case, since this gas can be assumed as ideal due to the given data, we can use the following equation:

PV=nRT\\\\PV=\frac{m}{MM}RT

Thus, by solving for volume we obtain:

V=\frac{mRT}{MM*P}

So we can plug in the temperature in Kelvins (537 K), the pressure in atmospheres (0.404 atm) and the molar mass (54 g/mol) to obtain:

V=\frac{87.8g*0.08206\frac{atm*L}{mol*K}*537K}{54g/mol*0.404atm}\\\\V=177.4L

Best regards!

6 0
3 years ago
Calculate the number of joules of heat energy needed to increase the temperature of 25.0 g of metal from 21.0 ºC to 80.0 ºC. The
Harman [31]

Answer:

Q = 768.47 J

Explanation:

Given that,

Mass of the metal, m = 25 g

Initial temperature, T₁ = 21.0 ºC

Final temperature, T₂ = 80.0 ºC

The specific heat of the metal is 0.521 J/gºC.

We know that the heat released due to the change in temperature is given by :

Q=mc\Delta T\\\\=25\times 0.521\times (80-21)\\Q=768.47\ J

Hence, 768.47 J of heat energy will be needed.

7 0
3 years ago
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