Answer:
<h3>The answer is 41.05 %</h3>
Explanation:
The percentage error of a certain measurement can be found by using the formula

From the question
actual density = 0.95 g/mL
error = 0.95 - 0.56 = 0.39
So we have

We have the final answer as
<h3>41.05 %</h3>
Hope this helps you
Answer:
V₂ = 22.84 L
Explanation:
Given data:
Initial volume = 20.0 L
Initial pressure = 1.50 atm
Initial temperature = 23 °C (23 +273 = 296 K)
Final temperature = 271°C (271+273 = 544 K)
Final pressure = 3.50 atm
Final volume = ?
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1.50 atm × 29.0L ×544 K / 296 K × 3.50 atm
V₂ = 23664 atm .L. K / 1036 atm.K
V₂ = 22.84 L
Answer:
V = 177.4 L.
Explanation:
Hello there!
In this case, since this gas can be assumed as ideal due to the given data, we can use the following equation:

Thus, by solving for volume we obtain:

So we can plug in the temperature in Kelvins (537 K), the pressure in atmospheres (0.404 atm) and the molar mass (54 g/mol) to obtain:

Best regards!
Answer:
Q = 768.47 J
Explanation:
Given that,
Mass of the metal, m = 25 g
Initial temperature, T₁ = 21.0 ºC
Final temperature, T₂ = 80.0 ºC
The specific heat of the metal is 0.521 J/gºC.
We know that the heat released due to the change in temperature is given by :

Hence, 768.47 J of heat energy will be needed.