Ask question

Ask question

All categories

wolverine [178]

2 years ago

7

12. A photo album page can hold 6 photographs. You have 296 photographs. How many pages do you need?

1 answer:

enot [183]2 years ago

4 0

You need about 50 pages. but to be exact it’s 49.3333333...going on forever

You might be interested in

Don’t know how to do this!

hram777 [196]

U+(v-t)
that’s the answer!

8 0

3 years ago

Read 2 more answers

6⁄10 _______ 9⁄12 A. > B. ≤ C. = D.

Ivanshal [37]

6/10 is equal to 0.60
9/12 is equal to 0.75
your answer is not above for D but if D is < then that would be the correct answer :)

7 0

3 years ago

Read 2 more answers

ammie pays $30 for a bag that she buys at a discount of 50%. What is the price of the bag without the discount? A. $30 B. $45 C.

Liula [17]

This would be C. 60$

This is because if she got the bag for 50% off, 30 divided by 2 is 15$, 45 divided by 2 is 22.5, 60 divided by 2 is 30$ so option C. Would be your answer.

7 0

3 years ago

The data below give the number of books checked out of the school library by 15 students during one month. Make a frequency tabl

Alexeev081 [22]

Item | Frequency

0      | 2
1      | 5
2      | 4
3      | 3
5      | 1

Hope I helped!

5 0

2 years ago

Read 2 more answers

Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally

sasho [114]

Answer:

a) $P(X$

$P(z$

b) $P(X>7.0)=P(\frac{X-\mu}{\sigma}>\frac{7-\mu}{\sigma})=P(Z1.47)$

$P(z>1.47)=1-P(z$

c) $P(3$

$P(-0.882$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the thickness of a population, and for this case we know the distribution for X is given by:

$X \sim N(4.5,1.7)$

Where $\mu=4.5$ and $\sigma=1.7$

We are interested on this probability

$P(X$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X$

And we can find this probability using excel or the normal standard table:

$P(z$

Part b

We are interested on this probability

$P(X>3.0)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>7.0)=P(\frac{X-\mu}{\sigma}>\frac{7-\mu}{\sigma})=P(Z1.47)$

And we can find this probability using excel or the normal standard table:

$P(z>1.47)=1-P(z$

Part c

$P(3$

And we can find this probability using excel or the normal standard table liek this:

$P(-0.882$

3 0

3 years ago