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3 years ago

If the outliers are not included in the data set below, what is the mean of the data set?

2 answers:

5 0

The outliers in this set are 96 and 29. Without these outliers, the set becomes 42, 43, 46, 48, 57, 60, 59, 38, 68
the mean (or average) of this set is closest to 52.

lilavasa [31]3 years ago

4 0

As the guy before me stated, "The outliers in this set are 96 and 29. Without these outliers, the set becomes 42, 43, 46, 48, 57, 60, 59, 38, 68
the mean (or average) of this set is closest to 52." Sorry I just want to be the brainliest answer sorry

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sveta [45]

D. Line sw
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3 years ago

A Shopkeeper

Sergio [31]

Answer:

The cost of bicycle is Rs1000

Step-by-step explanation:

Let x be the cost of bicycle

Total profit gained by the shopkeeper by selling at labelled price = 20%

Suppose he sell the bicycles at at 5% discount

Which means that the total profit he learn after discount will be:

20% -5% = 15%

The shopkeeper earns a profit of 15% if he sells at discount.

Profit gained by shopkeeper is:

15% of x = 15/100 · x

15% of x = 0.15x

Thus the profit gained will be 0.15x. As profit gained is equal to 150, we can say that

0.15x = 150

x = 1000

The cost of bicycle is Rs1000

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3 years ago

SOLVE 7-9 I WILL GIVE BRAINLIST

Mashcka [7]

Answer:

7. Approximately 402.7 inches or 2pi times 64

8. 31.83 To solve this you know 2pi r is an equation for the radius. 2πr=200 and r=200/2π=100/π= 31.83.

9. The one with pi in the equation because 3.14 is only a piece of pi but the symbol represents the whole number which goes on forever.

Step-by-step explanation:

7 0

2 years ago

What does it mean when it ask hat is the constant of proportionality in pages per hour?

Vinvika [58]

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3 years ago

The area of the shaded segment is 100cm^2. Calculate the value of r.

Reil [10]

Hello,

The formula for finding the area of a circular region is: $A= \frac{ \alpha *r^{2} }{2}$

then:
$A_{1} = \frac{80*r^{2} }{2}$

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

$cos(40)= \frac{h}{r} \\ \\ h= r*cos(40)\\ \\ \\ sen(40)= \frac{b}{r} \\ \\ b=r*sen(40)$

Now we can find its area:
$A_{2}=2* \frac{b*h}{2} \\ \\ A_{2}= [r*sen(40)][r*cos(40)]\\ \\A_{2}= r^{2}*sen(40)*cos(40)$

The subtraction of the two areas is 100cm^2, then:

$A_{1}-A_{2}=100cm^{2} \\ (40*r^{2})-(r^{2}*sen(40)*cos(40) )=100cm^{2} \\ 39.51r^{2}=100cm^{2} \\ r^{2}=2.53cm^{2} \\ r=1.59cm$

Answer: r= 1.59cm

7 0

2 years ago

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