Lets be a price of the calculator - $ a
then , after using the coupon, you need to pay $(a-18)
and after using 15% discount , you need to pay (1-0.15)a=0.85a
then, if
(a-18) will be more than 0.85a, you should prefer 0.15 % discount, because it will be cheaper,
a-18> 0.85a
a-0.85a>18
0.15a > 18
a>120, that means that if the price of the calculator more than $120, 15% discount is better,
but if the price of the calculator is less than $120, you should choose $ 18 coupon.
for example, we have the price of the calculator $100
100-18=82,
100*0.85 =85, coupon is better.
If the price of the calculator $200
200-18=182,
200*0.85=170, so 15% discount is better
if price of the calculator is $120,
120-18=102
120*0.85=102,
it will not matter, what you are going to use, because you are going to pay the same amount of money
Answer:
Step-by-step explanation:
m= y2 - y1/x2 - x1
m= -3 - 8
/1 - 2
m=-11/-1
m=11
Answer:
181 mi^2
Step-by-step explanation:
Dimensions of large rectangle, on the left, are 6 mi by 8 m; area is 48 m^2;
Dimensions of small rectangle, in the middle of the diagram, are 4 mi by 5 mi, or 20 mi^2; area is 20 mi^2.
Dimensions of circle: r = 12 mi; area of quarter circle is (1/4)(3.14)(12 mi)^2, or 113 mi^2.
Total area is 113 mi^2 + 20 mi^2 + 48 mi^2, or 181 mi^2
The wheel has diameter 60 cm = 0.60 m, and thus circumference π(0.60 m) ≈ 5.923 m.
In one complete revolution, a point on the edge of the wheel covers this distance, so that the wheel has an angular speed of
(13.2 m/s) * (1/5.923 rev/m) ≈ 2.229 rev/s
There are 60 seconds to each minute, and 60 minutes to each hour, so converting to rev/h gives
(2.229 rev/s) * (60 s/min) * (60 min/h) ≈ 8024 rev/h
The equation only is true for objects with negligible air resistance. A feather does not have this property.
Using the equation shown:
50 = -16t^2
t^2 = 50/16 = 3.125
t = sqrt(3.125) = 1.77 seconds
