Answer:
impossible
Step-by-step explanation:
by definition, the sums of two lengths of a triangle must be greater than either side. Since 3+8 < 12, it is clearly impossible to make a triangle.
Answer: C
<u>Step-by-step explanation:</u>
In order to find the inverse, transpose the matrix then find the determinant of each 2 x 2 matrix within it.
![Q=\left[\begin{array}{ccc}2&2&3\\1&1&1\\3&2&1\end{array}\right] \qquad \rightarrow \qquad Q^T=\left[\begin{array}{ccc}2&1&3\\2&1&2\\3&1&1\end{array}\right]](https://tex.z-dn.net/?f=Q%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%262%263%5C%5C1%261%261%5C%5C3%262%261%5Cend%7Barray%7D%5Cright%5D%20%5Cqquad%20%5Crightarrow%20%5Cqquad%20Q%5ET%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%261%263%5C%5C2%261%262%5C%5C3%261%261%5Cend%7Barray%7D%5Cright%5D)
![det\left[\begin{array}{cc}1&2\\1&1\end{array}\right] =\bold{-1}\qquad det\left[\begin{array}{cc}2&2\\3&1\end{array}\right]=\bold{-4}\qquad det\left[\begin{array}{cc}2&1\\3&1\end{array}\right] =\bold{-1}\\\\\\\\det\left[\begin{array}{cc}1&3\\1&1\end{array}\right] =\bold{-2}\qquad det\left[\begin{array}{cc}2&3\\3&1\end{array}\right]=\bold{-7}\qquad det\left[\begin{array}{cc}2&1\\3&1\end{array}\right] =\bold{-1}\\](https://tex.z-dn.net/?f=det%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%262%5C%5C1%261%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cbold%7B-1%7D%5Cqquad%20det%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%262%5C%5C3%261%5Cend%7Barray%7D%5Cright%5D%3D%5Cbold%7B-4%7D%5Cqquad%20det%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%261%5C%5C3%261%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cbold%7B-1%7D%5C%5C%5C%5C%5C%5C%5C%5Cdet%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%263%5C%5C1%261%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cbold%7B-2%7D%5Cqquad%20det%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%263%5C%5C3%261%5Cend%7Barray%7D%5Cright%5D%3D%5Cbold%7B-7%7D%5Cqquad%20det%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%261%5C%5C3%261%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cbold%7B-1%7D%5C%5C)
![det\left[\begin{array}{cc}1&3\\1&2 \end{array}\right] =\bold{-1}\qquad det\left[\begin{array}{cc}2&3\\2&2\end{array}\right]=\bold{-2}\qquad det\left[\begin{array}{cc}2&1\\2&1\end{array}\right] =\bold{0}](https://tex.z-dn.net/?f=det%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%263%5C%5C1%262%20%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cbold%7B-1%7D%5Cqquad%20det%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%263%5C%5C2%262%5Cend%7Barray%7D%5Cright%5D%3D%5Cbold%7B-2%7D%5Cqquad%20det%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%261%5C%5C2%261%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cbold%7B0%7D)
![Q^{-1}=\large\left[\begin{array}{ccc}1&-4&1\\-2&7&-1\\-1&-2&0\end{array}\right]](https://tex.z-dn.net/?f=Q%5E%7B-1%7D%3D%5Clarge%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-4%261%5C%5C-2%267%26-1%5C%5C-1%26-2%260%5Cend%7Barray%7D%5Cright%5D)
Answer:
Step-by-step explanation:
If the upper triangle has a right angle at Island C, we need only use the Pythagorean Theorem to find x:
(10 mi)^2 + (20 mi)^2 = x^2, so that
x^2 = 100 mi^2 + 400 mi^2 = 500 mi^2, which reduces to
x = +10√5 mi
Note that the shortest side (10 mi) is adjacent to a 30 degree angle. Thus, the upper triangle is a 30-60-90 triangle, meaning that the Pythagorean Theorem DOES apply here.
Next time, please incude ALL of the verbal instructions. Thank you.
Answer:
if ur du ur us du
Step-by-step explanation:
ur ydxurxru
Answer:
30.25=5+1.20t
Step-by-step explanation:
you do the cost then add the fee with the minutes on the trampoline
