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Sholpan [36]
3 years ago
14

Find the length of the third side. If necessary, write in simplest radical form. 10 7

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
6 0

Answer:

\sqrt{51}

Step-by-step explanation:

10²-7² (C squared minus B squared equals A squared) (basically Pythagorean theorem but reversed)

100-49= 51 (square the numbers and subtract)

\sqrt{51}  

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Chris rents a car for a total of £375 The rental charges are £150 for the first day and £75 per day after that. For how many day
valkas [14]

Answer:

4 days in total

Step-by-step explanation:

3 0
3 years ago
Could someone give me the answers do these please
Debora [2.8K]
5. (0,1)
6. (-2,-2)
7. (-1,-3)
8. (-3, 2)
5 0
3 years ago
Read 2 more answers
Find the sum of the following series
vazorg [7]

Answer:

a) 820

b)450

c)  -540

d) -294

e) 1440

f) 1425

Step-by-step explanation:

a) it is an arithmetic progression with ratio=4

   a1=3,

     a2=3+r=3+4=7.....

    a20=a1+19r

so a20=3+19*4=3+76=79

S=(a1+an)*n/2 where n=20

so S=(3+79)*20/2=820

b) a15=a1+14*r=2+14*4=2+56=58

S=(a1+a15)*15/2=(2+58)*15/2=60*15/2=30*15=450

It is the same formula for all  the exercises

S=(a1+an)*n/2 ,     where n is the number of terms

c) a40=30+39*(-3)=30-87=-57

So S=(30-57)*40/2=-540

d) a14=5+13*(-4)=5-52=-47

S=(5-47)*14/2=-42*14/2=-42*7=-294

e) it is 5+7+9+......+75

nr of  terms  = (an-a1) :r+1=(75-5):2+1=36

S=(5+75)*36/2=36*40=1440

f) ratio=7-4=3

the  same formula for n= (91-4):3+1=87:3+1=29+1=30

S=(4+91)*30/2=95*30/2=2850/2=1425

8 0
4 years ago
Can someone solve this quick plz
Gwar [14]

Answer:

length = x + 5

Step-by-step explanation:

Given

area = x² + 8x + 15 and area = length × width

We require to factorise x² + 8x + 15

Consider the factors of the constant term (+ 15) which sum to give the coefficient of the x- term (+ 8)

The factors are + 5 and + 3, since

5 × 3 = 15 and 5 + 3 = 8, thus

x² + 8x + 15 = (x + 5)(x + 3)

x + 3 is the width, thus x + 5 is the length

5 0
3 years ago
Examine the intersection of these lines:
Leto [7]

Answer:

∠B and ∠F

∠F and ∠E . . . already listed in the problem statement, so may not be considered an "other pair"

Step-by-step explanation:

∠C and ∠F are vertical angles, so are congruent. Then any angle complementary to one of those will also be complementary to the other.

Likewise, ∠B and ∠E are vertical angles and congruent. Any angle complementary to one of them will also be complementary to the other. Here, ∠E and ∠F are listed as complementary, so we know ∠B and ∠F will be also.

3 0
3 years ago
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