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3 years ago

X squared + ysquared-6y=-5

1 answer:

8 0

Standard Form of the circle:

$x^{2} +(y-3) ^{2} =14$

For y:

y=3 (+/-) $\sqrt{-x} ^{2} +14$

For x:

x= $\sqrt{-y ^{2} } +6y+5

and

- \sqrt{-y} ^{2} +6y+5$

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Mario got a part time job mowing lawns. On Monday he charged his neighbor $25 to mow his lawn, then spent $6 to refill his lawn

ss7ja [257]

Answer:

Step-by-step explanation:

Step one:

He charged $25 and spent $6 on gas on Monday.

then he made 25-6= $19 mowing his neighbor's lawn.

the next day is Tuesday(we are not told he spent any amount on gas on Tuesday).

So he mowed his Grandparents yard for $20.

total money saved for Monday and Tuesday is

19+20= $39

<u>Hence he has $39 for mowing both yards</u>

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3 years ago

Which of the following is least likely to be an advantage of scientific models?

Nutka1998 [239]

Answer:

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Step-by-step explanation:

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3 years ago

Solve for the distance between (13,55) and (61,22). Round your answer to the nearest hundredth.

Neporo4naja [7]

Answer:

Step-by-step explanation:

position 1: (13,55)

position 2: (61,22)

distance = $\sqrt{(p_{x2}-p_{x1})^{2} + (p_{y2}-p_{y1} )^{2}}$

distance = $\sqrt{(61-13)^{2} + (22-55)^{2}}$

distance = $\sqrt{(48^{2} + (-33)^{2} }$

distance = $\sqrt{2304 + 1089}$

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3 years ago

Some parts of California are particularly earthquake-prone. Suppose that in one metropolitan area, 32% of all homeowners are ins

Bumek [7]

Answer:

$P(X = 0) = 0.2138$

$P(X = 1) = 0.4025$

$P(X = 2) = 0.2841$

$P(X = 3) = 0.0891$

$P(X = 4) = 0.0105$

Step-by-step explanation:

For each homeowner, there are only two possible outcomes. Either they have invested in earthquake insurance, or they have not. The probability of a home owner having invested in earthquake insurance is independent from other homeowners. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$