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olganol [36]
3 years ago
13

Can you please help me answer these two please

Mathematics
2 answers:
Natalija [7]3 years ago
6 0
What’s the question asking for?
Brrunno [24]3 years ago
4 0

Answer:

I don't know what your looking for there is no question

Step-by-step explanation:

2+2=3 so let me know if that helps

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You work 35 hours/week for 52 weeks and are given the option to be paid hourly or to go on salary. In which situation will you e
rjkz [21]

Answer:

Hourly

Step-by-step explanation:

if you work for that long and for that many hours you would get alot of money in about a month or two.

4 0
3 years ago
Read 2 more answers
What is the vertex of a parabola defined by the equation <br> x = 5y2?
QveST [7]

Find the critical points of f(y):Compute the critical points of -5 y^2
To find all critical points, first compute f'(y):( d)/( dy)(-5 y^2) = -10 y:f'(y) = -10 y
Solving -10 y = 0 yields y = 0:y = 0
f'(y) exists everywhere:-10 y exists everywhere
The only critical point of -5 y^2 is at y = 0:y = 0
The domain of -5 y^2 is R:The endpoints of R are y = -∞ and ∞
Evaluate -5 y^2 at y = -∞, 0 and ∞:The open endpoints of the domain are marked in grayy | f(y)-∞ | -∞0 | 0∞ | -∞
The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:The open endpoints of the domain are marked in grayy | f(y) | extrema type-∞ | -∞ | global min0 | 0 | global max∞ | -∞ | global min
Remove the points y = -∞ and ∞ from the tableThese cannot be global extrema, as the value of f(y) here is never achieved:y | f(y) | extrema type0 | 0 | global max
f(y) = -5 y^2 has one global maximum:Answer: f(y) has a global maximum at y = 0

3 0
3 years ago
How many solutions does this equation have? How do you know?<br><br> 8x +14 - 4x = 9 + 4x - 5
MAVERICK [17]

Answer:

no solutions.

Step-by-step explanation:

8x + 14 -4x = 9+4x -5

8x-4x -4x = 9-5-14

0x = -10

anything multiplied by 0 is 0, so it's impossible to get -10 by multiplying by 0

5 0
3 years ago
Consider randomly selecting a student at a large university. Let A be the event that the selected student has a Visa card, let B
Tems11 [23]

Answer:

0.75

Step-by-step explanation:

Given,

P(A) = 0.6, P(B) = 0.4, P(C) = 0.2,

P(A ∩ B) = 0.3, P(A ∩ C) = 0.12, P(B ∩ C) = 0.1 and P(A ∩ B ∩ C) = 0.07,

Where,

A = event that the selected student has a Visa card,  

B = event that the selected student has a MasterCard,  

C = event that the selected student has an American Express card,

We know that,

P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C)

= 0.6 + 0.4 + 0.2 - 0.3 - 0.12 - 0.1 + 0.07

= 0.75

Hence, the probability that the selected student has at least one of the three types of cards is 0.75.

5 0
3 years ago
Step by step show answer for problem 3-3×6+2
storchak [24]
Do it according to the order of operations
(P)E^MxD/A+S-
the answer would be     -13

4 0
3 years ago
Read 2 more answers
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