The answer is d hope this helps
Let <em>f(x</em>, <em>y</em>, <em>z)</em> = <em>z</em> - arctan(<em>x y</em>). Compute the gradient of <em>f</em> at the point (0, 3, 0):
∇ <em>f(x</em>, <em>y</em>, <em>z)</em> = (-<em>y</em> / (1 + <em>x</em>²<em>y</em>²), -<em>x</em> / (1 + <em>x</em>²<em>y</em>²), 1)
∇ <em>f </em>(0, 3, 0) = (-3, 0, 1)
This vector is orthogonal to the surface <em>z</em> = <em>f(x</em>, <em>y)</em>. Then the equation of the tangent plane is
∇ <em>f </em>(0, 3, 0) • (<em>x</em>, <em>y</em> - 3, <em>z</em>) = 0
(-3, 0, 1) • (<em>x</em>, <em>y</em> - 3, <em>z</em>) = 0
-3<em>x</em> + <em>z</em> = 0
<em>z</em> = 3<em>x</em>
Answer:
150.8ft²
Step-by-step explanation:
A=2πrh+2πr2=2·π·3·5+2·π·32≈150.79645ft²
I'm guessing it is 10? or 7?
Answer:
The equation of the linear function is f(x) = -3x - 4
Step-by-step explanation:
The form of the equation of the linear function is f(x) = m x + b, where
- m is the slope of the line which represent the function
- b is the y-intercept which is value f(x) at x = 0
The rule of the slope is m = Δy/Δx, where
- Δx = x2 - x1 and Δy = y2 - y1
- (x1, y1) and (x2, y2) are two points on the line
∵ f(x) = y
∴ The coordinates of any point belongs to the function are (x, y)
∵ f(-4) = 8 and f(2) = -10
∴ The points are (-4, 8) and (2, -10)
∵ x1 = -4 and y1 = 8
∵ x2 = 2 and y2 = -10
→ Find Δx and Δy
∴ Δx = 2 - (-4) = 2 + 4 = 6
∴ Δy = -10 - 8 = -18
→ Substitute them in the rule of the slope
∵ m =
∴ m = -3
→ Substitute it in the form of the equation above
∴ f(x) = -3x + b
→ To find b substitute x by -4 and f(x) by 8
∵ 8 = -3(-4) + b
∴ 8 = 12 + b
→ Subtract 12 from both sides
∵ 8 - 12 = 12 - 12 + b
∴ -4 = b
→ Substitute it in the equation
∴ f(x) = -3x + (-4)
∴ f(x) = -3x - 4
∴ The equation of the linear function is f(x) = -3x - 4