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3 years ago

13

Robert is a dairy farmer. His favorite cow, Annabelle, produces 7 gallons of milk per day. One gallon of milk weighs 8.6 pounds.

How many pounds of milk does Annabelle produce each day?

1 answer:

nirvana33 [79]3 years ago

4 0

Answer:

60.2

Step-by-step explanation:

8.6pounds×7gallons

=60.2pounds

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The edges of a cube are 5 centimeters each and the diagonal of a face is approximately 7 centimeters. What is the approximate ar

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Step-by-step explanation:

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2 years ago

Read 2 more answers

12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5

Gnesinka [82]

$\large\underline{\sf{Solution-}}$

Given that,

In <u>triangle TPQ, </u>

RS || PQ,

RS = 3 cm,

PQ = 6 cm,

ar(∆ TRS) = 15 sq. cm

As it is given that, <u>RS || PQ</u>

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

$\rm\implies \: \triangle TPQ \: \sim \: \triangle TRS \: \: \: \: \: \: \{AA \}$

<u>Now, We know </u>

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)} = \dfrac{ {PQ}^{2} }{ {RS}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{ {6}^{2} }{ {3}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{36 }{9}$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = 4$

$\rm\implies \:ar( \triangle \: TPQ) = 60 \: {cm}^{2}$

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2 years ago

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3 years ago

What’s the correct answer for this?

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3 years ago

Assume that the random variable X is normally distributed, with mean muequals45 and standard deviation sigmaequals10. Compute t

saul85 [17]

Answer:

0.1069 = 10.69%

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

$\mu = 45, \sigma = 10$

Between 57 and 69

This is the pvalue of Z when X = 69 subtracted by the pvalue of Z when X = 57. So

X = 69

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{69 - 45}{10}$

$Z = 2.4$

$Z = 2.4$ has a pvalue of 0.9918

X = 57

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{57 - 45}{10}$

$Z = 1.2$

$Z = 1.2$ has a pvalue of 0.8849

0.9918 - 0.8849 = 0.1069 = 10.69%

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3 years ago