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mamaluj [8]
2 years ago
9

If the sine of angle a is 15/17 what is the cosine of angle a

Mathematics
1 answer:
Aleonysh [2.5K]2 years ago
5 0

Answer:

sin A = opp/hyp = 15/17

Right triangle

Therefor

a² + b² = c²

adj² + opp² = hyp²

adj² + 15² = 17²

adj² = 17² - 15²

adj² = 289 - 225

adj² = 64

adj = 8

Cos = adj/hyp

cos A = 8/17 <–––––

Step-by-step explanation:

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Be-1 where on the boat are registration numbers placed?
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3 years ago
Please help me I don’t understand how to do it. If you can please use a data table to explain how to do it.
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Answer:

The 70% mixture makes up 0.7 liters of the solution whereas the 60% mixture makes up 2.8 liters of the solution.

Step-by-step explanation:

Let us have x liters of the .7 mixture and y liters of the .6 mixture.

We want total liters to be 3.5 which means we need x+y=3.5 . I don't like the decimal in the equation so I'm going to multiply both sides by 10: 10x+10y=35

We also need the .7x+.6y=.62(3.5) . I hate the decimal business going on in this question so I'm going to multiply by 1000 which gives 700x+600y=62(35) .

So we have the system

700x+600y=62(35)

10x+10y=35

I'm going to setup this up for linear combination/elimination.

Multiply bottom equation by 60.

700x+600y=62(35)

600x+600y=60(35)

Subtract equations (bottom from top):

(700-600)x+(600-600)y=35(62-60)

Simplify:

100x+0y=35(2)

100x=70

Divide both sides by 100:

x=70/100

x=7/10

Going back to x+y=3.5 along with x=7/10 or .7 liters to find y.

y=3.5-x with x=.7

y=3.5-0.7

y=2.8

The 70% mixture makes up 0.7 liters of the solution whereas the 60% mixture makes up 2.8 liters of the solution.

Pic added.

Another way to do problem:

.7x+.6(3.5-x)=.62(3.5)

Multiply and distribute:

.7x+2.1-.6x=2.17

Combine like terms on left:

.1x+2.1=2.17

Subtract 2.1 on both sides:

.1x=.07

Multiply both sides by 10:

x=0.7 liters

Now the other acid solution is 3.5-0.7 which is 2.8 litera.

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