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Kazeer [188]
4 years ago
12

The statewide pass rates for ENGL&101 across Washington state community colleges is 68%. An instructor in the English depart

ment at CBC believes rates at CBC may be higher than the state average. This study can be stated as a formal hypothesis test in the following way:
H0 : p=0.68
HA: p > 0.68
To perform his study, he took a random sample of 250 students at CBC that had taken
ENGL&101, and found that 179 had passed the course.
Using your g from the last question, calculate the test statistic for the hypothesis test. Round your answer to two decimal places.
Mathematics
1 answer:
Mila [183]4 years ago
6 0

Answer:

<em>The calculated value Z=1.2413 < 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is accepted </em>

<em>An instructor in the English department at CBC believes rates at CBC may be equal to the state average</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given Population proportion </em>

<em>                                     P=68%= 0.68</em>

<em>Sample proportion </em>

<em>                             </em>p^{-} =\frac{x}{n} = \frac{179}{250} = 0.716<em></em>

<em>Null hypothesis : H₀ : p = 0.68</em>

<em>Alternative Hypothesis :H₁ : p > 0.68</em>

<u><em>Step(ii)</em></u><em>:-</em>

<em>Test statistic</em>

<em>                          </em>Z = \frac{p^{-}-P }{\sqrt{\frac{P Q}{n} } }<em></em>

<em>                         </em>Z = \frac{0.716-0.68 }{\sqrt{\frac{0.68 X 0.32}{250} } }<em></em>

<em>                        Z = 1.2413</em>

<em>Level of significance </em>

<em>              </em>Z_{0.05} = 1.96<em></em>

<em>The calculated value Z=1.2413 < 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is accepted </em>

<em>An instructor in the English department at CBC believes rates at CBC may be equal to the state average</em>

<em></em>

<em></em>

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