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hammer [34]
4 years ago
14

I need help solving this.

Mathematics
1 answer:
butalik [34]4 years ago
8 0
I can not solve this it is too blurry i'm sorry
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Marie buys lunch for $8.42. She pays with $10 bill and two quarters. How much change does she receive?
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2 dollar bills, one nickel, and three pennies ($2.08) :)

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In quadrilateral ABCD, diagonals AC And BD bisect one another
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Segment AP is congruent to segment CP. Segment BP is congruent to segment AP Sides AB and BC are congruent. Triangles BCP and CDP are congruent.
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For a standard normal distribution, find the approximate value of p (negative 0.78 less-than-or-equal-to z less-than-or-equal-to
topjm [15]

The approximate value of P(-0.78 ≤ Z ≤ 1.16) is obtained being 0.6593

<h3>How to get the z scores?</h3>

If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z score.

If we have  X \sim N(\mu, \sigma)

(X is following normal distribution with mean \mu and standard deviation \sigma)

then it can be converted to standard normal distribution as

Z = \dfrac{X - \mu}{\sigma}, \\\\Z \sim N(0,1)

(Know the fact that in continuous distribution, probability of a single point is 0, so we can write

P(Z \leq z) = P(Z < z) )

Also, know that if we look for Z = z in z-tables, the p-value we get is

P(Z \leq z) = \rm p \: value

For this case, we have to find:

P(-0.78\leq Z \leq 1.16)

It can be rewritten as:

P(-0.78\leq Z \leq 1.16) = P(Z \leq 1.16) - P(Z < -0.78) \\P(-0.78\leq Z \leq 1.16) = P(Z \leq 1.16) - P(Z \leq -0.78)

The p-values for Z = 1.16 and Z = -0.78 from the z-table is found as 0.8770 and 0.2177 respectively, and therefore, we get:

P(-0.78\leq Z \leq 1.16) = P(Z \leq 1.16) - P(Z \leq -0.78)\\P(-0.78\leq Z \leq 1.16) = 0.8770 - 0.2177 = 0.6593

Thus, the approximate value of P(-0.78 ≤ Z ≤ 1.16) is obtained being 0.6593

Learn more about z-score here:

brainly.com/question/21262765

8 0
2 years ago
3.(8 points)Consider the following experiment:Experiment: A bag contains 3 red balls, 4 blue balls, 4 green balls and 3yellow ba
MakcuM [25]

Answer:

3 / 91

Step-by-step explanation:

Given :

Red balls = 3

Blue balls = 4

Green balls = 4

Yellow balls = 3

Total number of balls = (3+4+4+3) = 14

Sample space :

RR, BB, GG, YY, RB, BR, BG, GB, YG, GY, YR, RY, BY, YB, GR, RG

Probability of drawing two red balls without replacement :

1st draw :

P(red) = number of red balls / total number of balls

P(red) = 3/14

2nd draw :

P(red) = 2 / 13

Hence,

P(RR) = 3/14 * 2/13 = 6 / 182 = 3 / 91

5 0
3 years ago
Jennifer has measured the amount of rain water in several different beakers for a science experiment. The amounts she measured a
andreev551 [17]
The answer is D.1.29 liters..hope that helped
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