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RoseWind [281]
3 years ago
5

Which of the following functions have only one point that is not in the domain? Select all that apply. (There are 2 answers)

Mathematics
1 answer:
densk [106]3 years ago
3 0

Answer:

  B.  f(x) = 3/(x^2 +2x +1)

  E.  f(x) = 5/(3+x)

Step-by-step explanation:

The above functions have denominators that are zero at one point. For B, that point is x=-1; for E, that point is x=-3. When the denominator is zero, the function is undefined, so the corresponding x-value must be excluded from the domain.

__

As written, choice D also qualifies. This is because the function written in the answer list here is ...

f(x)=\dfrac{1}{x^2}+5x+4

It will be undefined for x=0.

_____

<em>Comment on writing rational functions</em>

When the division symbol (/ or ÷) is used with a denominator that is a product or sum, that product or sum must be enclosed in parentheses. When the expression is typeset, the division bar acts as a grouping symbol. When the expression is written in text, a grouping symbol, such as parentheses, must be added.

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Answer:

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}

Step-by-step explanation:

Given

8x^{-10}y^6 - 2x^2y^{-8}

Required

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Rewrite as:

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6}{x^{10}} - \frac{2x^2}{y^8}

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8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}

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Step-by-step explanation:

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Step-by-step explanation:

Hope this helps!! Have an amazing day!!

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hello!!!!

the answer is 280

im not really sure... read the description.... since i dont see a picture attached i dont know the figure shape which makes it difficult to guarantee the correct answer for you....

please read the explanation.. it always helps...

Step-by-step explanation:

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