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3 years ago

Yuri writes this inequality:

Mathematics

2 answers:

pochemuha3 years ago

8 0

Answer:

A. No

B. Yes

C. No

Step-by-step explanation:

I took the test online in K12 and when I reviewed it said that those are the correct answers.

Minchanka [31]3 years ago

5 0

A. no
b. yes
c. no
hope this helped!!!

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15 is the nearest whole number to that number

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Answer: the first one

Step-by-step explanation:

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Why is 5/7 less than 8/10

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So this question is just a comparison problem.
If you split a chocolate bar into seven pieces, and ate 5 of them, you would have eaten less than if it were split into 10 pieces and you ate 8.

Another way to see this is if we did it mathematically.
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3 years ago

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Which Venn diagram shows the correct relationship among different set of numbers and correct numbers placement of -648

MA_775_DIABLO [31]

Answer:

Explanation:

The whole numbers are the numbers that we use to count like 1, 2, 3, ...

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Therefore, -648 is an integer number.

Finally, the rational numbers are numbers that can be written as a/b, where a and b are integers.

So, the answer is A because rational numbers contain integer numbers, integer numbers contain whole numbers and -648 is a integer number.

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1 year ago

Express the function y(t)= 4 sin 2πt + 15 cos 2πt in terms of (a) a sine term only. (b) Determine the amplitude, the period, the

Bond [772]

Answer:

See the step by step solution

Step-by-step explanation:

Consider a more general case of the form $a\sin(x)+b\cos(x)$ . We want to express it as a sine term only by using the following formula $\sin(\alpha+\beta) = \sin(\alpha)\cos(\beta)+\sin(\beta)\cos(\alpha)$

The trick consists on find a number $\beta \in [0,2\pi]$ such that $\cos(\beta) = a, \sin(\beta)=b$ . But, note that since $\cos^2(\beta)+\sen^2(\beta)=1$ it is most likely that $a^2+b^2neq 1$ . Then, we will use the following equations:

$\cos(\beta) =\frac{a}{\sqrt[]{a^2+b^2}=A,\sin(\beta) =\frac{b}{\sqrt[]{a^2+b^2}=B$

Then, problem turns out to be

$a\sin(x)+b\cos(x)= \sqrt[]{a^2+b^2}(A\sin(x)+B\cos(x)) =\sqrt[]{a^2+b^2}(\sin(x)\cos(\beta)+\sin(\beta)\cos(x))=\sqrt[]{a^2+b^2}\sin(x+\beta)$ ,

where $\beta = \tan^{-1}(\frac{B}{A})= \tan^{-1}(\frac{b}{a}). So, note that the frequency is the same. Then, a) Taking a=4 and b= 15 we have that 4 sin 2πt + 15 cos 2πt= [tex]\sqrt[]{15^2+4^2}\sin(2\pi t + \tan^{-1}\frac{15}{4})$

b) The amplitude is $\sqrt[]{15^2+4^2} = \sqrt[]{241}$ . Since $2\pi rad/s = 1 Hz$ the frequency is 1 Hz. The period is given by \frac{2\pi}{2\pi} = 1.

c) The function's graph is attached

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