Let's evaluate 3x + 4 when x=5

1 answer:

6 0

It is simple
Step 1) substitute x = 5 into the equation
3x +4
3(5) + 4 gives you 3 times 5 + 4
The answer is 15 + 4 which is 19

Now substitute a and b into the equation 3(a) + 4(b) when the a = 6 and b = 5
Hereby 3(6) + 4(5)
3 * 6 = 18 and 4* 5 = 20
18 + 20 = 38
The answer is 38

Now finally
Substitute a and b Into the equation
3(3) + 4(6)
9+ 24 = 33

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Answer:

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Step-by-step explanation:

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Rewrite the equation 8x + 6x^2 -7=x^2 in standard form and identify a, b, and c.

Vladimir79 [104]

Answer:

$5x^2+8x-7=0\\a=5\\b=8\\c=-7$

Step-by-step explanation:

The standard form of a quadratic is $ax^2+bx+c=0$ . You need to subtract the x^2 from the right to set the quadratic equal to 0. Then a,b, and c are equal to the values of the coefficients in front of the terms.