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3 years ago

10

The corporate team-building event will cost $18 if it has 6 attendees. How many attendees can there be, at most, if the budget f

or the corporate team-building event is $48? Solve using unit rates.

1 answer:

leonid [27]3 years ago

5 0

1) Find the unit rate

$18/6 attendees = 3

2) Apply the unit rate to find the answer

$48/$3= 16 attendees

Therefore, there can be 16 attendees if the budget is $48.

Hope this helps!

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#12 with explanation please

4vir4ik [10]

Answer:

30.01 units

Step-by-step explanation:

<u>Given vertices WXYZ:</u>

W(-4,5), X(2,4), Y(3, -4), Z(-1, -6)

Perimeter is the sum of the side length.

<u>Use distance formula to find each side:</u>

WX = $\sqrt{(2+4)^2+(4-5)^2} =\sqrt{37}$ ≈ 6.08
XY = $\sqrt{(3-2)^2+(-4-4)^2} =\sqrt{65}$ ≈ 8.06
YZ = $\sqrt{(-1-3)^2+(-6+4)^2} =\sqrt{20}$ ≈ 4.47
WZ = $\sqrt{(-1+4)^2+(-6-5)^2} =\sqrt{130}$ $\sqrt{(-1+4)^2+(-6-5)^2}=\sqrt{130}$ ≈ 11.40

<u>Find perimeter:</u>

P = 6.08 + 8.06 + 4.47 + 11.40 = 30.01 units

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2 years ago

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