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3 years ago

The variable used to predict changes in the values of another value is called the response variable.

1 answer:

7 0

I think the statement given above is false. The variable used to predict changes in the values of another value is not called the response variable. The variable used to predict another variable is called the independent, predictor or explanatory variable. Hope this answers the question.

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The table shows a pattern of exponents. What is the pattern as the exponents decrease?

Marrrta [24]

Answer:

Option C is correct.

Step-by-step explanation:

We need to find the pattern as the exponent decreases.

the first value in the table is 125.

if we divide 125 by 5 i.e 125/5 we get 25

the next value in the table is 25

if we divide 25 by 5 i.e 25/5 we get 5

the next value in the table is 5

if we divide 5 by 5 i.e 5/5 we get 1

the next value in the table is 1

if we divide 1 by 5 i.e 1/5 we get 1/5

the next value in the table is 1/5

if we divide 1/5 by 5 i.e 1/5*5 we get 1/25

the next value in the table is 1/25

So, the pattern is if we divide the previous value by 5 we get the next value in the table.

So, Option C is correct.

5 0

3 years ago

Read 2 more answers

Hi, so i have a question and i'm giving away free points so here's the question! If you answer ill put out another question and

Shtirlitz [24]

Answer:

1. Saturday

2(a) 10,944

2(b) 32700

3. (16,24)

Step-by-step explanation:

8 0

3 years ago

Trevion is training for a marathon. In February, he ran XLVII miles for his training. In January, he was only able to run XXIV m

Sonja [21]

Answer:

c.23

Step-by-step explanation:

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3 0

3 years ago

Round 863 to the nearest ten

anygoal [31]

Step-by-step explanation:

$863 \approx \: 860$

6 0

3 years ago

Read 2 more answers

) An instructor gives his class a set of 18 problems with the information that the next quiz will consist of a random selection

RSB [31]

Answer:

The probability the he or she will answer correctly is 1.5%

Step-by-step explanation:

In all, there are 18 problems. In this question, the order of which the problems are sorted for the quiz makes no difference. For example, if the question A of the quiz is P1 and question B P2, and question A P2 and question B P1, it is the same thing.

There are 18 problems and 9 are going to be selected. So, there is going to be a combination of 9 elements from a set of 18 elements.

A combination of n elements from a set of m objects has the following formula:

$C_{(m,n)} = \frac{m!}{n!(m-n)!}$

In this question, m = 18, n = 9. So the total number of possibilities is:

$T_{p} = C_{(18,9)} = \frac{18!}{9!(18-9)!} = 48620$

Now we have to calculate the number of desired outcomes. This number is a combination of 9 elements from a set of 13 elements(13 is the number of problems that the student has figured out how to do).

Now, m = 13, n = 9. The number of desired possibilities is:

$D_{p} = C_{(13,9)} = \frac{13!}{9!(13-9)!} = 715$

The probability is the number of desired possibilities divided by the number of total possibilities. So

$P = \frac{715}{48620} = 0.015 = 1.5%$

The probability the he or she will answer correctly is 1.5%

3 0

3 years ago