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3 years ago

The variable used to predict changes in the values of another value is called the response variable.

1 answer:

7 0

I think the statement given above is false. The variable used to predict changes in the values of another value is not called the response variable. The variable used to predict another variable is called the independent, predictor or explanatory variable. Hope this answers the question.

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Finger [1]

Given:

In triangle ABC, AB = AC, AD is angle bisector and measure of angle C is 49 degrees.

To find:

The value of x and y.

Solution:

In triangle ABC,

$AB=AC$ (Given)

So, triangle ABC is an isosceles triangle and by the definition of base angles the base angles of isosceles triangle are congruent.

In isosceles triangle ABC,

$\angle B\cong \angle C$

$m\angle B\cong m\angle C$

$m\angle B\cong 49^\circ$

The angle bisector of an isosceles triangle is the median and altitude of the triangle. So, the angle bisector is perpendicular to the base.

$m\angle ADB=90^\circ$

$x^\circ=90^\circ$

In triangle ABD,

$m\angle DAB+m\angle ABD+m\angle ADB=180^\circ$ [Angle sum property]

$y^\circ+49^\circ+x^\circ=180^\circ$

$y^\circ+49^\circ+90^\circ=180^\circ$

$y^\circ=180^\circ-49^\circ-90^\circ$

$y^\circ=41^\circ$

Therefore, the correct option is B.

3 0

3 years ago

A regulation baseball field measures 90 feet between each base. What is the distance around the bases in meters?

Alex787 [66]

assuming that the bases are placed correctly, the bases connected draw a square, each side being 90 ft long. We multiply 90 by the amount of sides(4) to find the total distance/perimeter = 360.

3 0

3 years ago

The circumference of a circle is 37.68 meters. What is the area of the circle?

german

The area of the circle is 112.98 m squared

4 0

3 years ago

What is the main purpose of being on offense

TiliK225 [7]

B to defend your goal

4 0

3 years ago

Solve each system by substitution. -5x + 3y = 3 and -4x + y = 1

taurus [48]

$\left\{\begin{array}{ccc}-5x+3y=3\\-4x+y=1&|\text{add 4x to both sides}\end{array}\right\\\\\left\{\begin{array}{ccc}-5x+3y=3\\y=4x+1&(*)\end{array}\right\\\\\text{Substitute }\ (*)\ \text{to the first equation}\\\\-5x+3(4x+1)=3\qquad\text{use distributive property}\\\\-5x+(3)(4x)+(3)(1)=3\\\\-5x+12x+3=3\qquad\text{subtract 3 from both sides}\\\\7x=0\qquad\text{divide both sides by (-5)}\\\\\boxed{x=0}\\\\\text{Substitute the value of x to}\ (*):\\\\y=4(0)+1\\y=0+1\\\boxed{y=1}\\\\Answer:\ x=0\ and\ y=1.$

5 0

3 years ago