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alexira [117]
3 years ago
13

What is the slope of the line through (-5, -3) and (-5, -7)?

Mathematics
1 answer:
Paul [167]3 years ago
5 0

Answer:

The answer is undefined.

Step-by-step explanation:

Slope is found using this equation: y-y1/x-x1. Fill in the coordinates to this equation. It should now look like this. -7--3/-5--5. When subtracting from two negatives, it changes into a positive. For example, -7--3 becomes -7+3, which equals -4. The same thing applies for the second part. -5--5 becomes -5+5, which equals 0. So, your slope is -4/0. However, when a 0 is in the denominator, it becomes undefined. So, the answer is undefined.

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Step-by-step explanation:

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4) (Assume AR is tangent)<br>Given: AR 12<br>SR - 7.7<br>Find: cs (Round to nearest tenth.)​
andreev551 [17]

The length of CS is 11.0

Explanation:

Given that the length of the tangent AR is 12

The length of SR is 7.7

To find: The length of CS

The<u> tangent secant theorem</u> states that "if a tangent and a secant are drawn from an external point to a circle, then the square of the measure of the tangent is equal to the product of the measures of the secant’s external part and the entire secant."

Applying the tangent secant theorem, we have,

AR^2=SR\times RC

Rewriting the above equation, we get,

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Simplifying, we have,

144=59.29+7.7CS

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Dividing both sides by 7.7, we have,

11.0013=CS

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11.0=CS

Thus, the length of CS is 11.0

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