A dextrose/saline aqueaout solution doctors commonly use to replace fluids in the body contains 1.75g/L NaCl and 40.0g/L dextros
1 answer:
<em>Mixed molarity = 0.25 M</em>
<em>Osmotic pressure solution: 6.15 atm</em>
<h3><em>Further explanation</em></h3>Osmotic pressure is the minimum pressure given to the solution so that there is no osmotic displacement from a more dilute solution to a more concentrated solution.
General formula:
π = osmotic pressure (atm)
M = solution concentration (mol / l)
R = constant = 0.08205 L atm mol-1 K-1
T = Temperature (Kelvin)
Mixing solution
To find the molarity of the mixed solution we can use the following formula:
Vc. Mc = V1.M1 + V2.M2
where
Mc =Mixed molarity
Vc = mixed volume
Mr. NaCl = 58.5
Mr. Dextrose = C₆H₁₂O₆ = 180
mole NaCl = gram / Mr
mole NaCl = 1.75 / 58.5 = 0.03
Dextrose mole = 40/180 = 0.22
Assuming 1 liter of solution
M mixture = mole NaCl + mole dextrose / 1 liter
M mixture = 0.03 + 0.22 / 1 L
M mix = 0.25 M
T = 25 + 273 = 298 K
The osmosis pressure of the solution becomes:
π = 0.25. 0.0825. 298 = 6.15 atm
<h3><em>Learn more</em></h3>The osmotic pressure brainly.com/question/8195553
<h3><em>Answer details </em></h3>Grade: Senior High School
Subject: Chemistry
Chapter: Colligative property
Keywords: osmotic pressure, molarity, mole,dextrose, NaCl
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Answer:
2 water + sugar + lemon juice → 4 lemonade
Moles of water present in 946.36 g of water=\frac{946.36 g}{236.59 g/mol}=4 mol=
236.59g/mol
946.36g
=4mol
Moles of sugar present in 196.86 g of water=\frac{196.86 g}{225 g/mol}=0.8749 mol=
225g/mol
196.86g
=0.8749mol
Moles of lemon juice present in 193.37 g of water=\frac{193.37 g}{257.83 g/mol}=0.7499 mol=
257.83g/mol
193.37g
=0.7499mol
Moles of lemonade in 2050.25 g of water=\frac{2050.25 g}{719.42 g/mol}=2.8498 mol=
719.42g/mol
2050.25g
=2.8498mol
As we can see that number of moles of lemon juice are limited.
So, we will consider the reaction will complete in accordance with moles of lemon juice.
1 mole lemon juice reacts with 2 mol of water,then 0.7499 mol of lemon juice will react with:
\frac{2}{1}\times 0.7499 mol = 1.4998 mol
1
2
×0.7499mol=1.4998mol of water
Mass of water used = 1.4998 mol × 236.59 g/mol=354.8376 g
Water remained unused = 946.36 g - 354.8376 g =591.5223 g
1 mole lemon juice reacts with mol of sugar,then 0.7499 mol of lemon juice will react with:
\frac{1}{1}\times 0.7499 mol = 0.7499 mol
1
1
×0.7499mol=0.7499mol of water
Mass of sugar used = 0.7499 mol × 225 g/mol = 168.7275 g
Sugar remained unused = 196.86 g - 28.1325 g
1 mole of lemon juice gives 4 moles of lemonade.
Then 0.7499 mol of lemon juice will give:
\frac{4}{1}\times 0.7499 mol=2.996 mol
1
4
×0.7499mol=2.996mol of lemonade
Mass of lemonade obtained = 2.996 mol × 719.42 g/mol = 2157.9722 g
Theoretical yield of lemonade = 2157.9722 g
Experimental yield of lemonade = 2050.25 g
Percentage yield of lemonade:
\frac{\text{Experimental yield}}{\text{theoretical yield}}\times 100
theoretical yield
Experimental yield
×100
\frac{2050.25 g}{2157.9722 g}\times 100=95.00\%
2157.9722g
2050.25g
×100=95.00%
