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Alex17521 [72]
3 years ago
13

____________ tautomers have a C=O and an additional C-H bond.

Chemistry
1 answer:
Roman55 [17]3 years ago
4 0

Ch = sh = why and find the stuff

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a sample of a compound contains 60gC and 5.05gH.it molar mass is 78.12g/mol what is the compound molecular formula
elena55 [62]
(60)/(60+5.05)=.922367 C
1-0.922367=0.07763259 H
(0.922367)(78.12)=72.05534204 C
(0.07763259)(78.12)=6.06 H
72.05534204/(12.01)=6 C
6.06/1.01=6 H
Empirical= CH
Molecular=C6H6
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What characteristics does the serval have that make it well-suited to life on the savanna ?
nika2105 [10]
It is very camouflaged this way it will survive longer then most other animals

5 0
3 years ago
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Medical implants and high-quality jewelry items for body piercing are frequently known by a trade name, G23Ti, which means "surg
mrs_skeptik [129]

Answer:

Ti6Al4V1 or Ti6Al4V

Explanation:

So, from the question above we are given the following Important data or parameters or information which is going to help us in solving this question and they are;

The "surgical-grade" titanium is made up of 64.3% titanium, 24.19% aluminum and 11.42% vanadium.

This is a stoichiometry Question so in order to be able to solve this question one must have the basic knowledge of stoichiometry, it is advisable that one revise it.

So, let us delve right into the solution of this question. Recall that, the formula for Calculating the number of moles = mass/molar mass.

Hence, the number of moles of titanium,Ti = 64.3/47.87 = 3 moles.

Also, the number of moles of aluminum = 24.19/26.98 = 0.8966

For vanadium; 11.42/51 = 0.22

The next step is to divide each number of moles component by the lowest number of mole, that is;

Ti = 1.34/ 0.22 = 6; Al = 0.8966/0.22= 4 and V = 0.22/0.22 = 1.

Thus, the emperical formula is = Ti6Al4V.

7 0
2 years ago
57. The orbitals of an atom are distinguished from each other on the basis of their size, shape, and orientation in
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False they are distinguished by probability
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What is the pH of a Koh solution that has [H+]=1.87×10^-13M
xenn [34]
PH=-log[H⁺]
pH=-log(1.87×10⁻¹³)
pH=12.72

I hope this helps.  Let me know if anything is unclear.
7 0
3 years ago
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