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3 years ago

Unknown element X is a metal that ionically bonds to sulfur. Is the formula, X3S feasible? Why or why not?

Chemistry

2 answers:

Irina18 [472]3 years ago

5 0

No, it is not feasible. Three metallic ions cannot provide the exact number of electrons that one sulfur needs for the ionic bond

Aleks04 [339]3 years ago

5 0

Answer: No it is not feasible.

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Here the non metal is sulfur having an oxidation state of -2 and thus the formula of an ionic compound containing sulfur can never be $X_3S$ as the neutral compound is formed by exchange of oxidation states. Thus the subscript of X has to be 2.

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What is the molarity of a solution prepared by dissolving 2.5 grams of LiNO3 in sufficient water to make 60.0 mL of solution?

Murrr4er [49]

Answer: hope this helps

To make molar NaCl solutions of other concentrations dilute the mass of salt to 1000ml of solution as follows:

0.1M NaCl solution requires 0.1 x 58.44 g of NaCl = 5.844g.

0.5M NaCl solution requires 0.5 x 58.44 g of NaCl = 29.22g.

2M NaCl solution requires 2.0 x 58.44 g of NaCl = 116.88g.

Explanation:

6 0

3 years ago

Read 2 more answers

Question 3 (1 point)

pentagon [3]

Full question:

The IUPAC name for CH3CH2C≡CCH3 is:

Answer:

2-pentyne

Explanation:

To name hydrocarbons, you first you have to identify the longest carbon chain. There are 5 carbons in this chain, so we know the name is "pent".

You then have to identify the presence of any double or triple bonds. If double bonds, it is an alkene, if triple bonds, it is an alkyne. In this case there is a triple bond, so we know the hydrocarbon is pentyne.

You then number the chain to give the lowest number to the triple bond. It could either be 4 (countnig carbons from left to right) or 2 (from right to left). Therefore, the answer is 2-pentyne.

5 0

3 years ago

PLEASE ANSWER

Otrada [13]

Answer:

The answer is D) White Light!

7 0

3 years ago

A sample of Xe gas is observed to effuse through a pourous barrier in 4.83 minutes. Under the same conditions, the same number o

Solnce55 [7]

Answer:

28.93 g/mol

Explanation:

This is an extension of Graham's Law of Effusion where $\frac{R1}{R2} = \sqrt{\frac{M2}{M1} } = \frac{t2}{t1}$

We're only talking about molar mass and time (t) here so we'll just concentrate on $\sqrt{\frac{M2}{M1} } = \frac{t2}{t1}$ . Notice how the molar mass and time are on the same position, recall effusion is when gas escapes from a container through a small hole. The time it takes it to leave depends on the molar mass. If the gas is heavy, like Xe, it would take a longer time (4.83 minutes). If it was light it would leave in less time, that gives us somewhat an idea what our element could be, we know that it's atleast an element before Xenon.

Let's plug everything in and solve for M2. I chose M2 to be the unknown here because it's easier to have it basically as a whole number already.

$\sqrt{\frac{M2}{131} } = \frac{2.29}{4.83}$

The square root is easier to deal with if you take it out in the first step, so let's remove it by squaring each side by 2, the opposite of square root essentially.

$(\sqrt{\frac{M2}{131} } )^2= (\frac{2.29}{4.83})^2$

${\frac{M2}{131} } = (0.47)^2$

${\frac{M2}{131} } = 0.22$

M2= 0.22 x 131

M2= 28.93 g/mol

8 0

2 years ago

What is the appropriate chemical formula for Iron(III) Sulfate? Sulfate is SO_4^2 Fe3SO4 O a . Fe2(SO4)3 O b. O c. Fe2SO4 O d. F

AnnyKZ [126]

<u>Answer:</u> The chemical formula of Iron (III) sulfate is $Fe_2(SO_4)_3$

<u>Explanation:</u>

Iron is the 26th element of periodic table having electronic configuration of $[Ar]3d^64s^2$ .

To form $Fe^{3+}$ ion, this element will loose 3 electrons.

Sulfate ion is a polyatomic ion having chemical formula of $SO_4^{2-}$

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for Iron (III) sulfate is $Fe_2(SO_4)_3$

4 0

3 years ago