To solve
if you have |a|=b, solve a=b and a=-b
|4x+12|=16
solve
4x+12=16 and 4x+12=-16
minus 12 both sides
4x=4 and 4x=-28
divide both sides by 4
x=1 and x=-7
a function that model the number of people that receives email in week t is
.
<u>Step-by-step explanation:</u>
Here we have , Tobias sent a chain letter to his friends . The number of people who receives the email increases by a factor of 4 in every 9.1 weeks , and can be modeled by a function P, which depends on the amount of time t weeks . Tobias initially sent letter to 37 friends . We need to write a function that model the number of people that receives email in week t . Let's find out:
Basically it's an exponential function as
, In question initial value is 37 & and for every 9.1 weeks there is increase in people by a factor of 4 i.e.
⇒ 
But , wait ! People increase in every 9.1 weeks not every week so modified equation will be :
⇒
Therefore , a function that model the number of people that receives email in week t is
.
Answer:
I hope this helps a little bit
Part A. You have the correct first and second derivative.
---------------------------------------------------------------------
Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.
-------------------------------------------------------------
Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out
To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0.
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well.
Answer:
(0, -1)
Step-by-step explanation:
There are multiple ways of solving this however- since both equations are already in Y-Intercept form, we will use the "Equal Values Method"
First, since both equations are equal to Y, we can set them equal to each other and solve for X

To start, you must eliminate the fraction using a "fraction buster" multiply EVERYTHING by 4 then simplify.

Since we still have a fraction, we shall do it one more time. This time we multiply by 3

Now, solve how you normally would.
9x = 6x
-6x
3x = 0
X = 0
Now, since we know what X would equal in the solution, we are able to plug in X as 0 in one of our equations. We can choose the first one!

Now solve which would lead to y = -1
You have your solution as
(X,Y)
(0,-1)
Hope this helps!