Question

The point-slope from of the equation of the line that passes through (-4, -3) and (12, 1) is y- 1 = 1/4 (x - 12). What is the standard from of the equation from this line?

Answer 1

Answer:

$\large\boxed{x-4y=8}$

Step-by-step explanation:

The standard form of an equation of a line:

$Ax+By=C$

We have the equation in point-slope form. Convert:

$y-1=\dfrac{1}{4}(x-12)$             multiply both sides by 4

$4y-4=x-12$              add 4 to both sides

$4y=x-8$            subtract x from both sides

$-x+4y=-8$             change the signs

$x-4y=8$