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shusha [124]
3 years ago
6

Can I get a list of all eras and one thing that lived during that era?

Biology
1 answer:
ch4aika [34]3 years ago
5 0
Cenozoic Era: Deinotherium

Mesozoic Era: Ichthyosaur

Paleozoic Era: Trilobites

Precambrian Era: Ediacarans
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Which pair do you predict would have the largest difference in mass-specific basal metabolic rate?
Effectus [21]

Answer:

The pair's options needed to complete the question are

A. dog and cat

B. lion and dog

C. lion and cat

D. cat and mouse

E. they are all likely to be the same

D. CAT AND MOUSE IS THE ANSWER

Explanation:

Mass-specific basal metabolic rate (mass-specific BMR), is the resting energy expenditure per unit body mass per day.

mass-specific BMR mammals decreases as weight increases i.e

Metabolic rates of animals are allometric functions of body size

D. Cat and mouse is the answer

5 0
3 years ago
The Hadza and the Datog are both groups of tribes in Africa. Which of these has the traditionally higher-starch diet?
Hoochie [10]

Answer:

The Datog has the traditionally higher-starch diet.

Explanation:

The Datog has traditionally consume higher-starch diet than the Hadza. The people of Hadza tribe take their food from the forest including berries, fiber-rich tubers, honey and meat etc. They search the forest in order to obtain food for themselves and their families while the Datog people obtain food by planting starch rich crops such as maize, beans and millet. so we can say that the Datog people consume higher-starch diet.

6 0
3 years ago
Which phase of a cell's life cycle is occurring when the chromatids are pulled apart and move to the opposite ends of the cell?
s2008m [1.1K]
A.Anaphase
Interphase is DNA replication metaphase the cell is in the middle and prophase is the second stage
8 0
3 years ago
Read 2 more answers
Write out the form of the partial fraction decomposition of the function (See Example). Do not determine the numerical values of
maw [93]

Answer:

a.\frac{A}{x}+\frac{B}{x^2}+\frac{C}{x^3}+\frac{Dx+E}{x^2+5}

b.\frac{A}{x+3}+\frac{B}{x-3}+\frac{C}{(x-3)^2}+\frac{D}{(x+3)^2}

Explanation:

a.We are given that

\frac{x^4+7}{x^5+5x^3}

\frac{x^4+7}{x^5+5x^3}=\frac{x^4+7}{x^3(x^2+5)}

Using partial fraction decomposition of the given function

\frac{x^4+7}{x^3(x^2+5)}=\frac{A}{x}+\frac{B}{x^2}+\frac{C}{x^3}+\frac{Dx+E}{x^2+5}

Using the formula

\frac{1}{x^3(x^2+a)}=\frac{A}{x}+\frac{B}{x^2}+\frac{C}{x^3}+\frac{Dx+E}{x^2+a}

b.\frac{2}{(x^2-9)^2}

\frac{2}{(x^2-3^2)^2}=\frac{2}{(x+3)^2(x-3)^2}

Using property a^2-b^2=(a+b)(a-b)

\frac{2}{(x+3)^2(x-3)^2}=\frac{A}{x+3}+\frac{B}{x-3}+\frac{C}{(x-3)^2}+\frac{D}{(x+3)^2}

Using the property

\frac{1}{x^2}=\frac{A}{x}+\frac{B}{x^2}

5 0
3 years ago
N men, anabolic steroids cause select one:
vodomira [7]
A shut down of normal testosterone production
5 0
3 years ago
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