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2 years ago

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Two real-valued functions, f(x) and g(x), are defined as f(x) = x2 + 6x + 9 and g(x) = x2 – 9. Find the results of combining the

se functions.

2 answers:

Elis [28]2 years ago

7 0

Answer:

6(x + 3)=(f-g)(x)

2x(x+3)=(f+g)(x)

next one is (f/g)(x)

then (f*g)(x) hope you can figure it out Plato btw

Step-by-step explanation:

pogonyaev2 years ago

4 0

I hope this helps you

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Every hour at work, you are able to ship out the same number of

never [62]

Answer:

its 6

Step-by-step explanation:

divided 12 with 2 and divided 30 with 5

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2 years ago

She has 12 apples. She sold 10 and made a $1 profit. How much did she sell each of the 10 apples for?

Papessa [141]

Answer:

0.10 each. just do 1 divided by 10

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3 years ago

Read 2 more answers

Solve the following system of equations using the substitution method.

Novay_Z [31]

X=2y
2x+5y=9

substitute the x=2y into the second equation
2(2y)+5y=9
multiple the 2y by 2. 4y+5y=9
combine like terms. 9y=9
divide the 9 out from both sides. y=1
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your answer is: x=2
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7 0

2 years ago

Factor out the coefficient 1/2d+6

Ratling [72]

To factor, we always have to look for common factors in the numbers given to us. In this case, in 1/2 and 6, the common factor is 1/2. Therefore, we will have to factor like so:

1/2d + 6 = 1/2 (d + 3)

Hope this helps!

4 0

2 years ago

Read 2 more answers

You recently sent out a survey to determine if the percentage of adults who use social media has changed from 66%, which was the

il63 [147K]

Answer:

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Of the 2809 people who responded to survey, 1634 stated that they currently use social media.

This means that $n = 2809, \pi = \frac{1634}{2809} = 0.5817$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 - 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.56$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 + 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.6034$

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

6 0

2 years ago