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mojhsa [17]
3 years ago
14

Multiply (-3/4) x (-2/9)

Mathematics
2 answers:
Aleksandr [31]3 years ago
7 0

Answer:

\huge{\boxed{~~Answer:\frac{1}{6}~ ~}}

Step-by-step explanation:

All~you~have~to~do~is~multiply~-3~with~-2~then~multiply~4~with~9.

You~should~be~getting~your~answer~as:

\frac{-3}{4}* \frac{-2}{9} =\frac{1}{6}

xeze [42]3 years ago
3 0

Answer:

\frac{1}{6}

Step-by-step explanation:

When multiplying fractions, you simply multiply numerator by numerator and denominator by denominator, and if possible, you later simplify the answer.

\frac{-3}{4} * \frac{-2}{9} = \frac{6}{36}

\frac{6}{36} / 6 = \frac{1}{6}

Hope it helped,

BiologiaMagister

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The first two terms in an arithmetic progression are -2 and 5. The last term in the progression is the only number in the progre
Rudik [331]

Given:

The first two terms in an arithmetic progression are -2 and 5.

The last term in the progression is the only number in the progression that is greater than 200.

To find:

The sum of all the terms in the progression.

Solution:

We have,

First term : a=-2

Common difference : d = 5 - (-2)

                                      = 5 + 2

                                      = 7

nth term of an A.P. is

a_n=a+(n-1)d

where, a is first term and d is common difference.

a_n=-2+(n-1)(7)

According to the equation, a_n>200.

-2+(n-1)(7)>200

(n-1)(7)>200+2

(n-1)(7)>202

Divide both sides by 7.

(n-1)>28.857

Add 1 on both sides.

n>29.857

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Sum of n terms of an A.P. is

S_n=\dfrac{n}{2}[2a+(n-1)d]

Substituting n=30, a=-2 and d=7, we get

S_{30}=\dfrac{30}{2}[2(-2)+(30-1)7]

S_{30}=15[-4+(29)7]

S_{30}=15[-4+203]

S_{30}=15(199)

S_{30}=2985

Therefore, the sum of all the terms in the progression is 2985.

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3 years ago
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