Answer:
The correct options are;
1) Write tan(x + y) as sin(x + y) over cos(x + y)
2) Use the sum identity for sine to rewrite the numerator
3) Use the sum identity for cosine to rewrite the denominator
4) Divide both the numerator and denominator by cos(x)·cos(y)
5) Simplify fractions by dividing out common factors or using the tangent quotient identity
Step-by-step explanation:
Given that the required identity is Tangent (x + y) = (tangent (x) + tangent (y))/(1 - tangent(x) × tangent (y)), we have;
tan(x + y) = sin(x + y)/(cos(x + y))
sin(x + y)/(cos(x + y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y))
(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y))
(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y)) = (tan(x) + tan(y))(1 - tan(x)·tan(y)
∴ tan(x + y) = (tan(x) + tan(y))(1 - tan(x)·tan(y)
Answer:
m-a = n
Step-by-step explanation:
a=m-n
Subtract m from each side
a-m = m-n-m
a-m = -n
Multiply each side by -1
-a+m = n
m-a = n
Abcdefghijklmnopqrstuvwxyz
ok
b to a
goes back 1 letter
then b to d
skips 3 letters forward
then d to e
1 forward
e to h
skips 3 forward
h to g
goes 1 back
g to k
goes 3 forward
pattern seems to be
1back, 3 forward, 1 forward, 3 forward, repeat
so we are at 3 forward after than 1 back, so the next one is 1 forward
1 forward from k is l
the next letter is L
Answer:
depends on what it is. like is it a dice or something you're pulling out of a bag.
Answer:
You did not even start the meeting them you want us to join . Silly
Step-by-step explanation:
6871383
how you doing?
how your day going?
