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Schach [20]
3 years ago
14

________ can exist without ________, but ________ cannot exist without ________.

Physics
1 answer:
Zolol [24]3 years ago
6 0
B.
Voltage can exist without current, but current cannot exist without voltage.
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Calculate the temperature increase in a 1.00-kg sample of water that results from the conversion of gravitational potential ener
Llana [10]

To solve this problem it is necessary to apply the concepts concerning the conservation of both potential and thermodynamic energy of the body. That is to say that as the body has a loss of potential energy it is gained in the form of thermal energy on water. If the potential energy is defined as

PE = mgh

Where,

m= mass

g = Gravitational acceleration

h = Height

And thermal energy is obtained as

Q = mC_p\Delta T

Where,

\Delta T = Change in Temperature

C_p = Specific Heat

m = Mass

We can equate this equation and rearrange to find the change at the Temperature, then

mgh = mC_p\Delta T

\Delta T = \frac{gh}{C_p}

Our values are given as,

C_p = 4186J/Kg\cdot K \rightarrow Specific Heat Water

Using energy conservation

g = 9.8m/s^2

h = 807m

Replacing,

\Delta T = \frac{(9.8)(807)}{4186}

\Delta T = 1.89K

Therefore the temperature increase in a 1kg sample of water is 1.89K

8 0
3 years ago
What must be your average speed in order to travel 350 km in 5.15 h? *
Alexxandr [17]
V= s/t
​
=
5.15/ 350
​
=68.0 km/h
3 0
3 years ago
Please help with this question ASAP!!!
Paladinen [302]
The answer is the second choice

7 0
4 years ago
On an alien planet, a simple pendulum of length 0.300 m has oscillation frequency 0.709 Hz. Find the period of the pendulum. Fin
sweet [91]

Answer:

1.41s

5.95m/s

0.2746m

Explanation:

The time period

T = 1/f

= 1/0.709s

= 1.41 seconds

We have

T = 2π√l/g

T² = 4π²l/g

g = 4π²l/T²

g = 4x3.14²x0.300/1.41²

g = 5.95m/s² this is the acceleration due to gravity.

Then the time period of the glide

T2 = 2π√m/k

Length of pendulum = l

Time period T

T2 = 2π√l/g

Then T1 = T2

2π√m/k = 2π√l/g

M/k = l/g

L = g.m/k

L = 5.95x0.450/9.75

L = 0.2746

This must be the length of the simple pendulum

8 0
3 years ago
What is the kinetic energy of a 10 kg ball moving at a rate of 2 m/s
Gnoma [55]

Answer:

20 J

Explanation:

KE = ½ mv²

KE = ½ (10 kg) (2 m/s)²

KE = 20 J

7 0
4 years ago
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