All categories

3 years ago

An object accelerates 12.0 m/s2 when a force of 6.0 Newton's is applied to it .What is the mass of the object?

Physics

1 answer:

AleksAgata [21]3 years ago

3 0

Answer:

Explanation:

This is a direct application of Newton's 2nd Law:

F = ma, where F is the force applied to an object, m is the mass of the object, and a is the acceleration of the object when this force is applied. Note: this is NOT the same as the acceleration due to gravity which is constant at -9.8 m/s/s or -32 ft/s/s. Filling in:

6.0 = m(12.0) so

m = .5 kg

You might be interested in

A diver shines a flashlight upward from beneath the water (n=1.33) at a 36.2° angle to the vertical. At what angle does the ligh

horrorfan [7]

Answer:

The flashlight leaves the water at an angle of 51.77°.

Explanation:

if n1 = 1.33 is the refractive index of water and ∅1 is the angle at which the flashlight shine beneath the water, and n2 = 1.0 is the refractive index of air and ∅2 is the angle the flashlight leaves the water.

Then, according to Snell's law :

n1×sin(∅1) = n2×sin(∅2)

sin(∅2) = n1×sin(∅1)/n2

= (1.33)×sin(36.2)/(1.0)

= 0.7855055×379

∅2 = 51.77°

Therefore, the flashlight leaves the water at an angle of 51.77°.

7 0

4 years ago

What is the magnitude (in N/C) and direction of an electric field that exerts a 4.00 x 10^−5 N upward force on a −2.00 µC charge

emmasim [6.3K]

Answer:

The magnitude of electric field is $1.25\times10^{14}\ N/C$ in downward.

Explanation:

Given that,

Force $F= 4.00\times10^{-5}\ N$

Charge q= -2.00 μC

We know that,

Charge is negative, then the electric field in the opposite direction of the exerted force.

We need to calculate the magnitude of electric field

Using formula of electric force

$F = qE$

$E = \dfrac{F}{q}$

$E=\dfrac{4.00\times10^{-5}}{-2.00\times1.6\times10^{-19}}$

$E=-1.25\times10^{14}\ N/C$

Negative sign shows the opposite direction of electric force.

Hence, The magnitude of electric field is $1.25\times10^{14}\ N/C$ in downward.

8 0

4 years ago

What si unit replaces pound

Artist 52 [7]

The SI unit of mass is the kilogram, and
the SI unit of force is the Newton.

8 0

4 years ago

A river with a flow rate of 7 m3/s discharges into a lake with a volume of 9,000,000 m3. The concentration of a particular VOC i

soldi70 [24.7K]

Answer:

The concentration downstream reduces to 0.03463mg/L

Explanation:

Initially let us calculate the time it is required to fill the lake, since for that period of time the pollutant shall remain in the lake before being flushed out.

Thus the detention period is calculated as

$t=\frac{V}{Q}\\\\t=\frac{9000000}{7}=1.285\times 10^{6}seconds\\\\\therefore t = 14.872days$

Now the concentration of the pollutant after 14.872 days is calculated as

$N_{t}=N_{0}e^{-kt}$

where

$N_{o}$ is the initial concentration

't' is the time elapsed after which the remaining concentration is calculated

k is the dissociation constant.

Applying values we get

$N_{t}=3\times e^{-0.3\times 14.872}$

$N_{t}=0.03463mg/L$

4 0

3 years ago

Dan is gliding on his skateboard at 4.00m/s . He suddenly jumps backward off the skateboard, kicking the skateboard forward at 6

frozen [14]

To solve this problem we will apply the concepts related to the conservation of the Momentum. For this purpose we will define the momentum as the product between mass and velocity, and by conservation the initial momentum will be equal to the final momentum. Mathematically this is,

$m_1u_1+m_2u_2 = m_1v_1+m_2v_2$