Answer:
C: increases
Explanation:
Temperature is directly proportional to volume. If the temperature of a substance increases, the volume also increases. If the temperature decreases the volume also decreases.
According to Charles's law "the volume of fixed mass of gas varies directly as its absolute temperature if the pressure remains constant". Although this is an ideal gas law, it is also applicable to most substances.
As the temperature is raised, the volume also behaves proportionally that way.
<h2>The net ionic equation that correspond to Fe(ClO4)2 +Na2CO3 is</h2>
<u>Fe ^2+(aq) +CO3^2-(aq) → FeCO3 (s)</u>
<h3>Explanation</h3><h3 /><h3>write the balance chemical equation</h3>
Fe(ClO4)2 (aq) + Na2CO3(aq)→ FeCO3 (s) + 2 NaClO4
<h3>write the ionic equation</h3>
Fe^2+(aq) + 2ClO4 ^-(aq) + 2Na^+(aq) +CO3^2- (aq) → FeCO3 (s) + 2Na^+ + 2ClO4^-
<h3>cancel the spectator ions in both side</h3>
- that is ( 2ClO4^- and 2Na+)
the ionic equation is therefore
<u>Fe^2+(aq) + CO3^2- →FeCo3(s)</u>
Mass number = number of protons + number of neutrons
mass number= 8 + 7= 15 ---> the answer is B.
The molar concentration of the KI_3 solution is 0.0833 mol/L.
<em>Step 1</em>. Calculate the <em>moles of S_2O_3^(2-)</em>
Moles of S_2O_3^(2-) = 25.00 mL S_2O_3^(2-) ×[0.200 mmol S_2O_3^(2-)/(1 mL S_2O_3^(2-)] = 5.000 mmol S_2O_3^(2-)
<em>Step 2</em>. Calculate the <em>moles of I_3^(-)
</em>
Moles of I_3^(-) = 5.000 mmol S_2O_3^(2-)))) × [1 mmol I_3^(-)/(2 mmol S_2O_3^(2-)] = 2.500 mmol I_3^(-)
<em>Step 3</em>. Calculate the <em>molar concentration of the I_3^(-)</em>
<em>c</em> = "moles"/"litres" = 2.500 mmol/30.00 mL = 0.083 33 mol/L
Answer:88.8%
Explanation:
%yield= actual yield/theoretical yield * 100/1
41.9/47.2*100/1= 88.8%
