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k0ka [10]
3 years ago
6

In a reaction between carbon monoxide and ferrous ferric oxide (Fe3O4), the theoretical yield in the experiment is calculated as

47.2 g iron. However, when a student performed the experiment, the actual yield was 41.9 g iron. Calculate the percentage yield.
Chemistry
1 answer:
Naya [18.7K]3 years ago
6 0

Answer:88.8%

Explanation:

%yield= actual yield/theoretical yield * 100/1

41.9/47.2*100/1= 88.8%

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viva [34]

Answer:

La distinción entre la química teóricamente teórica y la química avanzada es la química teórica teórica que se basa en un espiritualista, potente que percibe visualmente la autenticidad, mientras que la química espera que la autenticidad sea fundamentalmente mundana. Eso engendra una tremenda distinción, y la química nunca se hubiera alejado excepcionalmente de la remota posibilidad de que se hubiera quedado con el trascendentalismo antediluviano.

Explanation:

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During an experiment, a canister filled with hot water was added to a beaker filled with cold water. In which direction did the
Nady [450]

Answer:

A)

Explanation:

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3 0
3 years ago
What is the pressure of 5.0 mol nitrogen gas in a 2.0 L container at 286 K
g100num [7]
The "Ideal Gas Law Equations" is 
PV=nRT
P= Pressure (in Pascals)
V=Volume (in Liters)
n=amount, or <u>n</u>umber (in moles)
R= 8.3145 \frac{Pascals*Liters}{Moles*Kelvin} or \frac{PaL}{molK}
T= Temperature (In Kelvin)

P= \frac{nRT}{V}

Plug into the equation and you're good!
P=\frac{nRT}{V}
P =\frac{(5mol)(8.3145)(286K)}{2L}
P=5944.8675Pa

If your teacher cares about sig figs,
2 sig figs (significant figures)
P=5900Pa

For other units of pressure,
1 atm = 760 mmHG = 760 Torr = 101326 Pa = 1.01325 bar<u />
5 0
4 years ago
What type of microscope has a magnification less than 300x but allows you to view objects in 3D?
Sindrei [870]
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5 0
3 years ago
Read 2 more answers
Which of the following substances would you predict to have the highest DHvap? Group of answer choices CH3CH2CH2CH3 CH3CH2OH HF
Katyanochek1 [597]

Answer:

a) CH_3CH_2CH_2CH_3

Explanation:

In this question we have the following answer choices:

a) CH_3CH_2CH_2CH_3

b) CH_3CH_2OH

c) HF

d) CH_3Cl

e) HOCH_2CH_2OH

We have to remember the relationship between intermolecular forces and vapor pressure. If we have stronger intermolecular forces we will have less vapor pressure because the molecules have more interactions between them, so, the molecules will prefer to stay in a liquid state rather than a gaseous state. Now, we have to check each molecule:

a) CH_3CH_2CH_2CH_3 (Van der waals interactions)

b) CH_3CH_2OH (Hydrogen bonding)

c) HF (Hydrogen bonding)

d) CH_3Cl (Dipole-dipole interaction)

e) HOCH_2CH_2OH (Hydrogen bonding)

For molecules b, c and e we have <u>hydrogen bond to a heteroatom</u> (O, N, S, or P). In this case oxygen, therefore we will have <u>hydrogen bonding </u>interactions (a very strong interaction). So, we can discard these ones.

In molecule e, we have "Cl" bond to a "C" therefore we will have the presence of a <u>dipole</u> (due to the <u>electronegativity difference</u>). If we have a dipole, we will have a <u>dipole-dipole interaction</u> (a strong interaction, less than hydrogen bonding but still is a strong interaction).

In molecule a, we have only <u>Van der Waals interactions</u> because in this molecule we have only carbon and hydrogen atoms bonded by single bonds. So, we will have a n<u>on-polar molecule</u>. These interactions are the weakest interactions of all the molecules given. So, <u>if we have weaker interactions the molecules can be converted to a gas state more easily and we have more vapor pressure.  </u>

7 0
3 years ago
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