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3 years ago

Which formula should be used to calculate pressure and temperature changes if the volume remains constant

Chemistry

1 answer:

svlad2 [7]3 years ago

8 0

Answer:

P1 /T1 =P2/T2

Explanation:

ccording to the Gay- Lussac's Law,

" The pressure of given amount of gas is directly proportional to the temperature at a constant volume"

Mathematical expression:

P ∝ T

P = CT

P / T = C

As the temperature increase, the pressure also increase and vice versa.

The initial and final expression of volume and pressure can be written as,

P₁ / T₁ = P₂ / T₂

You might be interested in

If 298 mL of 0.575 M CuCl2 is diluted into 750 mL, what is the concentration of new solution?

Sonja [21]

Answer:

<h3>The answer is 0.228 M</h3>

Explanation:

To find the concentration of new solution we use the formula

$C_1V_1 = C_2V_2$

where

C1 is the concentration of the stock solution

V1 is the volume is the volume of the stock solution

C_2 is the concentration of the diluted solution

V2 is the volume of the diluted solution

Since we are finding the the concentration of new solution

$C_2 = \frac{C_1V_1}{V_2} \\$

From the question

C1 = 0.575 M

V1 = 298 mL

V2 = 750 mL

We have

$C_2 = \frac{0.575 \times 298}{750} \\ = 0.228466666...$

We have the final answer as

Hope this helps you

4 0

3 years ago

(1.) Using Beer's Law, How will the absorbance measured for the solutions change as the concentration of aspirin in solutions in

Vesnalui [34]

Answer:

(1) The absorbance of the aspirin in solutions will increase.

(2) [ASA]f = 3.79x10⁻⁴M

(3) [ASA]i = 3.79x10⁻³M

(4) m ASA = 0.171g

Explanation:

<u>The Beer's Law is expressed by:</u>

$A = \epsilon \cdot l \cdot C$ (1)

<em>where A: is the absorbance of the species, ε: is the molar attenuation coefficient, l: is the pathlength and C: is the concentration of the species</em>

(1) <u>From </u><u>equation (1)</u><u>, the relation between the absorbance of the species and its concentration is directly proportional,</u> so if the aspirin concentration in solutions increases, the absorbance of the solutions will also increase.

(2) Starting in the given expression for the relationship between absorbance and concentration of ASA, we can calculate its concentration in the solution:

$A = 1061.5 \cdot [ASA]$

$[ASA] = \frac{A}{1061.5} = 3.79 \cdot 10^{-4}M$

Therefore, the aspirin concentration in the solution is 3.79x10⁻⁴ M

(3) To calculate the stock solution concentration, we can use the next equation:

$V_{i} [ASA]_{i} = V_{f} [ASA]_{f}$

<em>where Vi: is the stock solution volume=10mL, Vf: is the solution diluted volume=100mL, [ASA]i: is the aspirin concentration of the stock solution and [ASA]f: is the aspirin concentration of the diluted solution</em>

$[ASA]_{i} = \frac{V_{f} \cdot [ASA]_{f}}{V_{i}} = \frac {100mL \cdot 3.79\cdot 10^{-4} M}{10mL} = 3.79 \cdot 10^{-3} M$

Hence, the concentration of the stock solution is 3.79x10⁻³M

(4) To determine the aspirin mass in the tablet, we need to use the following equation:

$m_{ASA} = \eta_{ASA} \cdot M_{ASA} = [ASA]_{i} \cdot V_{0} \cdot M_{ASA}$

<em>where η: is the aspirin moles = [ASA]i V₀, M: is the molar mass of aspirin=180.158g/mol, V₀: is the volume of the volumetric flask=250mL and [ASA]i: is the aspirin concentration in the volumetric flask which is equal to the stock solution=3.79x10⁻³M</em>

$m_{ASA} = 3.79 \cdot 10^{-3} \frac{mol}{L} \cdot 0.250L \cdot 180.158 \frac{g}{mol} = 0.171 g$