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Akimi4 [234]
3 years ago
11

*Asap*

Chemistry
1 answer:
ira [324]3 years ago
7 0

Answer:

(a).

order \: of \: A = 2 \\ order \: of \:B  = 0 \\ rate = k[A] {}^{2} [B]

(b)

0.32 \times  {10}^{ - 3}  = k {(0.12)}^{2} (0.15) \\ k = 0.148 \:  {mol}^{ - 2}  {dm}^{6}  {s}^{ - 1}

(c). The rate increases because kinetic energy of reactant molecules increases.

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4 0
3 years ago
The percentage composition of acetic acid is found to be 39.9% C, 6.7% H, and 53.4% O. What is the empirical formula of acetic a
anastassius [24]

Answer:

CH₂O

Explanation:

From the question given above, the following data were obtained:

Carbon (C) = 39.9%

Hydrogen (H) = 6.7%

Oxygen (O) = 53.4%

Empirical formula =?

The empirical formula of acetic acid can be obtained as follow:

C = 39.9%

H = 6.7%

O = 53.4%

Divide by their molar mass

C = 39.9 / 12 = 3.3

H = 6.7 / 1 = 6.7

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Divide by the smallest

C = 3.3 / 3.3 = 1

H = 6.7 / 3.3 = 2

O = 3.3 / 3.3 = 1

The empirical formula => CH₂O

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