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3 years ago

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Chemistry

1 answer:

ira [324]3 years ago

7 0

Answer:

(a).

$order \: of \: A = 2 \\ order \: of \:B = 0 \\ rate = k[A] {}^{2} [B]$

(b)

$0.32 \times {10}^{ - 3} = k {(0.12)}^{2} (0.15) \\ k = 0.148 \: {mol}^{ - 2} {dm}^{6} {s}^{ - 1}$

(c). The rate increases because kinetic energy of reactant molecules increases.

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Percent yield of 0.20 g of Al

elena-14-01-66 [18.8K]

Answer:

the dividend yield is 4%

Explanation:

The computation of the dividend yield is as follows:

Dividend yield = Dividend per share ÷ current share price per share

= ($0.20 × 4 quarters) ÷ $20

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The same is determined by applying the above formula

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3 years ago

At 298 K the standard enthalpy of combustion of sucrose is -5645 kJ/mol and the standard reaction Gibbs energy is -5798 kJ/mol.

natka813 [3]

Explanation:

The given data is as follows.

T = 298 K, $\Delta H^{o}$ = -5645 kJ/mol

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$\Delta G^{o}$ = $\Delta H^{o} - T \Delta S^{o}$

-5798 kJ/mol = -5645 kJ/mol - $298 \times \Delta S^{o}$

-153 kJ/mol = - $298 \times \Delta S^{o}$

$\Delta S^{o}$ = 0.513 kJ/mol K

Now, temperature is $37^{o}C$ = (37 + 273) K = 310 K

Since, $\Delta G$ = $\Delta H^{o} - T \Delta S^{o}$

= $-5645 kJ/mol - 310 K \times 0.513 kJ/mol K$

= (-5645 kJ/mol - 159.03 kJ/mol)

= -5804.03 kJ/mol

As, change in Gibb's free energy = maximum non-expansion work

$\Delta G = \Delta G_{310 K} - \Delta G_{298 K}$

= -5804.03 kJ/mol - (-5798 kJ/mol)

= -6.03 kJ/mol

Therefore, we can conclude that the additional non-expansion work is -6.03 kJ/mol.

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3 years ago

What does the questions “how much?” and “how many?” have in common?

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4 years ago

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Answer:

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Plastics are made from natural materials such as cellulose, coal, natural gas, salt and crude oil through a polymerisation or polycondensation process. Plastics are derived from natural, organic materials such as cellulose, coal, natural gas, salt and, of course, crude oil.

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3 years ago

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Answer : The number of moles of $CaC_2$ reacted was, 0.214 moles.