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steposvetlana [31]
3 years ago
7

In statistics, what term means "a numerical range around a sample mean accompanied with a statement of how confident one is that

the true population mean lies within the interval?
Mathematics
1 answer:
Alex Ar [27]3 years ago
3 0

Answer:

Confidence Interval for the mean

Step-by-step explanation:

Confidence interval is made using the observations of a <em>sample</em> of data obtained from a population, so it is constructed in such a way, that, with a certain <em>level of confidence </em>(this is the statement mentioned in the question), that is, one could have a percentage of probability that the interval, or range around the value obtained, frequently 95%, contains the true value of a population parameter (in this case, the population mean).  

It is one way to extract information from a population using a sample of it. This kind of information is what inference statistic is always looking for.

An <u>approximation</u> about how to construct this interval or range:

  1. Select a random sample.
  2. For the specific case of a <em>mean</em>, you need to calculate the mean of the <em>sample </em>(sample mean), and, if standard deviation is unknown or not mentioned, also calculate the sample standard deviation.
  3. With this information, and acknowledged that these values follows a standard normal distribution (a normal distribution with mean 0 and a standard deviation of 1), represented by random variable Z, one can use all this information to calculate a <em>confidence interval for the mean</em>, with a certain confidence previously choosen (for example, 95%), that the population mean must be in this interval or <em>range around this sample mean.</em>

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Step-by-step explanation:

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We would determine AB by applying the law of cosines

AB² = AP² + BP² - 2AP×BPCosP

AB² = 20² + 25² - 2 × 20 × 25 × Cos45

AB² = 1025 - 707.10678 = 317.89322

AB = √317.89322 = 17.83

We would determine the bearing of B from A by finding angle A. We would apply the sine rule.

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17.83 × SinA = 20Sin45 = 14.14

SinA = 14.14/17.83 = 0.79

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Therefore, bearing B from A is

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