2 years ago

What is the approximate circumference of the circle shown belowneed help fast

Mathematics

1 answer:

Lemur [1.5K]2 years ago

7 0

C
All u have to do is add 23.5 to 23.5

You might be interested in

An ice cream factory makes 100 quarts of ice cream in 5 hours how many quarts could be made in 36 hours

I am Lyosha [343]

Answer:

720 Quarts

Step-by-step explanation:

$\frac{100}{5} = \frac{x}{36}$

cross multiply

$\frac{100}{5}*\frac{36}{36} = \frac{x}{36}*\frac{5}{5}\\\\\frac{3,600}{180}=\frac{5x}{180}$

now that they are both divided by 180, we can eliminate it

$3,600=5x\\\\\frac{3,600}{5}=\frac{5x}{5}\\\\720=x$

7 0

2 years ago

Read 2 more answers

Solve the rational equation (3x^2+1)/(x-1) + x =4 + 4/(x-1)

natita [175]

Answer:

The answer to your question is letter D

Step-by-step explanation:

Rational equation

$\frac{3x^{2} + 1}{x - 1} + x = 4 + \frac{4}{x - 1}$

Simplify

$\frac{3x^{2} + 1 + x(x - 1)}{x - 1} = \frac{4(x - 1) + 4}{x - 1}$

Cancel the denominators and expand

3x² + 1 + x² - x = 4x - 4 + 4

Simplify

4x² - x + 1 - 4x = 0

4x² - 5x + 1 = 0

Factor

4x² - 4x - 1x + 1 = 0

4x(x - 1) - 1(x - 1) = 0

(4x - 1)(x - 1) = 0

x₁ = 1/4 x₂ = 1

4 0

2 years ago

Given that y=x^(1/3) , use calculus to determine an approximate value for ∛8030

Alex777 [14]

F(x) = x^(1/3)
f(8000) = 8000^(1/3) = 20

f'(x) = 1/3 * x^(-2/3)
f'(x) = 1/(3x^(2/3))
f'(8000) = 1/(3*8000^(2/3)) = 1/(3*400) = 1/1200

Linear approximation for f(x) about x = 8000
L(x) = f(8000) + f'(8000) (x−8000)
L(x) = 20 + 1/1200 (x−8000)

8030^(1/3) ≈ L(8030)
= 20 + 1/1200 (8030−8000)
= 20 + 30/1200
= 20 + 1/40
= 20.025

8 0

2 years ago

Plz help and explain ty

RoseWind [281]

$4^{-4} = \dfrac{1}{4^4} = \dfrac{1}{256}$