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Whitepunk [10]
3 years ago
6

Lea has 3/4 cup of laundry detergent left in detergent bottle. Each load of laundry requires 1/6 cup of detergent. How many load

s of laundry can Lea wash.
Mathematics
1 answer:
Stells [14]3 years ago
3 0
ANSWER

Lea can wash 4½ loads of laundry with the remaining detergent.

EXPLANATION

Quantity of detergent left
= \frac{3}{4}

Quantity required to watch each load
= \frac{1}{6}

Number of loads Lea can wash
= \frac{3}{4} \div \frac{1}{6}

We now simplify this by multiplying with the reciprocal

Number of loads Lea can wash

= \frac{3}{4} \times \frac{6}{1}

= \frac{3}{2} \times \frac{3}{1}

= \frac{9}{2}

= 4 \frac{1}{2}

Therefore Lea can wash 4½ loads of laundry with the remaining detergent.
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A metalworker has a metal alloy that is 15​% copper and another alloy that is 60​% copper. How many kilograms of each alloy shou
coldgirl [10]

18 kg of 15% copper and 72 kg of 60% copper should be combined by the metalworker to create 90 kg of 51% copper alloy.

<u>Step-by-step explanation:</u>

Let x = kg of 15% copper alloy

Let y = kg of 60% copper alloy

Since we need to create 90 kg of alloy we know:

x + y = 90

51% of 90 kg = 45.9 kg of copper

So we're interested in creating 45.9 kg of copper

We need some amount of 15% copper and some amount of 60% copper to create 45.9 kg of copper:

0.15x + 0.60y = 45.9

but

x + y = 90

x= 90 - y

substituting that value in for x

0.15(90 - y) + 0.60y = 45.9

13.5 - 0.15y + 0.60y = 45.9

0.45y = 32.4

y = 72

Substituting this y value to solve for x gives:

x + y = 90

x= 90-72

x=18

Therefore, in order to create 90kg of 51% alloy, we'd need 18 kg of 15% copper and 72 kg of 60% copper.

6 0
3 years ago
Solve 5y^2+20=80, where y is the real number
soldi70 [24.7K]

Answer:

2√3

Step-by-step explanation:

5y2+20=80

Step 1: Subtract 20 from both sides.

5y^2+20−20=80−20

5y^2=60

Step 2: Divide both sides by 5.

5y^2 /5 = 60/5

y2=12

Step 3: Take square root.

y=√12

y=2√3

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1500(1+0.04)^3 = 1687.30

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Step-by-step explanation:

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