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SashulF [63]
3 years ago
6

What is the value of x? Pls hurry!!!

Mathematics
1 answer:
eduard3 years ago
4 0

Answer:

C. 120

Step-by-step explanation:

Hope it helps!

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What is the distance between the points(-5,-1) and (-2,-6) ? Round to the nearest tenth if necessary.
Oksana_A [137]

Answer:

5.8

Step-by-step explanation:

the distance formula is

d =sqrt( (x2-x1)^2 + (y2-y1)^2 )

  = sqrt ( (-5 - -2) ^2 + (-1 - -6)^2 )

  = sqrt( (-5 +2) ^2 + (-1 +6)^2 )

= sqrt( (-3) ^2 + (5)^2 )

 = sqrt( 9+25)

 = sqrt(34)

  =5.830951895

Rounding to the nearest tenth

5.8

3 0
4 years ago
Read 2 more answers
Solve for z <br><br> z−4/9−1/3=5/9
Svetach [21]
4/3 because (check the picture)

3 0
3 years ago
Math help please?!?!?<br> I promise just some more then Im done!!
Talja [164]
Your answe would be a>-2 so just plug that in to the line and that will be your answer which is the second one
7 0
3 years ago
Read 2 more answers
Sin α = 21/29, α lies in quadrant II, and cos β = 15/17, β lies in quadrant I Find sin (α - β).
Sever21 [200]
\sin(\alpha-\beta)=\sin\alpha\cos\beta-\cos\alpha\sin\beta

\sin\alpha=\dfrac{21}{29}\implies \cos^2\alpha=1-\sin^2\alpha=\dfrac{400}{841}

Since \alpha lies in quadrant II, we have \cos\alpha, so

\cos\alpha=-\sqrt{\dfrac{400}{841}}=-\dfrac{20}{29}

\cos\beta=\dfrac{15}{17}\implies\sin^2\beta=1-\cos^2\beta=\dfrac{64}{289}

\beta lies in quadrant I, so \sin\beta>0 and

\sin\beta=\sqrt{\dfrac{64}{289}}=\dfrac8{17}

So

\sin(\alpha-\beta)=\dfrac{21}{29}\dfrac{15}{17}-\left(-\dfrac{20}{29}\right)\dfrac8{17}=\dfrac{475}{493}
8 0
3 years ago
3. The graph of f(x) = 4x² +4 is shown. State the domain, range, and end behavior of the function.​
Natalija [7]
The domain is all real numbers

The range is [4,infinity)

The end behavior is

As x—-> +infinity, f(x)—->+infinity

And as x——>-infinity, f(x)——>+infinity

Hope this helps!
8 0
2 years ago
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