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3 years ago

What is the formula that relates circumference and radius?

2 answers:

6 0

All the options are incorrect, if you're talking about circle! which is most common
C = 2πr..... It is the relation for Circle's if you're considering something else, then, please mention!

jonny [76]3 years ago

6 0

Answer:

The formula that relates circumference and radius is $C=2\pi r$ .

Step-by-step explanation:

The circumference of a circle is calculated by the formula

$C=2\pi r$

Where,

C is circumference of the circle.

r is radius of the circle.

π is 22/7 or 3.14.

In the given options π is not missing. So, all the given options are incorrect.

Therefore the formula that relates circumference and radius is $C=2\pi r$ .

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How do you translate the graph of f(x) = x3 left 4 units and down 2 units? Identify the equation of the graph

Marina CMI [18]

Answer:

The correct option is B.

Step-by-step explanation:

The given function is

$f(x)=x^3$

The translation of a function is defined as

$g(x)=f(x+a)+b$

If a>0, then the graph of f(x) shift a units left and if a<0, then the graph of f(x) shift a units right.

If b>0, then the graph of f(x) shift b units up and if b<0, then the graph of f(x) shift b units down.

It is given that the graph of f(x) shifts 4 units left and 2 units down. So, a=4 and b=-2.

$g(x)=f(x+4)+(-2)$

$g(x)=(x+4)^3-2$ $[\because f(x)=x^3]$

$y=(x+4)^3-2$

Therefore option B is correct.

8 0

3 years ago

Read 2 more answers

If four pounds of a certain candy cost $10 how manu pounds of that candy can be purchased for $12

dangina [55]

4.8 pounds, set it up as 4 over ten times x over 12, 4 times 12 divided by ten equals 4.8

8 0

3 years ago

Value of 3x^2 +4y^2 if x=2, y=1, and z= -3

Dennis_Churaev [7]

$3x^2+4y^2\\\\\text{Put the values of x=2, y=1 and z=-3 to the expression:}\\\\3(2^2)+4(1^2)=3(4)+4(1)=12+4=16$

4 0

3 years ago

Two streams flow into a reservoir. Let X and Y be two continuous random variables representing the flow of each stream with join

zlopas [31]

Answer:

c = 0.165

Step-by-step explanation:

Given:

f(x, y) = cx y(1 + y) for 0 ≤ x ≤ 3 and 0 ≤ y ≤ 3,

f(x, y) = 0 otherwise.

Required:

The value of c

To find the value of c, we make use of the property of a joint probability distribution function which states that

$\int\limits^a_b \int\limits^a_b {f(x,y)} \, dy \, dx = 1$

where a and b represent -infinity to +infinity (in other words, the bound of the distribution)

By substituting cx y(1 + y) for f(x, y) and replacing a and b with their respective values, we have

$\int\limits^3_0 \int\limits^3_0 {cxy(1+y)} \, dy \, dx = 1$

Since c is a constant, we can bring it out of the integral sign; to give us

$c\int\limits^3_0 \int\limits^3_0 {xy(1+y)} \, dy \, dx = 1$

Open the bracket

$c\int\limits^3_0 \int\limits^3_0 {xy+xy^{2} } \, dy \, dx = 1$

Integrate with respect to y

$c\int\limits^3_0 {\frac{xy^{2}}{2} +\frac{xy^{3}}{3} } \, dx (0,3}) = 1$

Substitute 0 and 3 for y

$c\int\limits^3_0 {(\frac{x* 3^{2}}{2} +\frac{x * 3^{3}}{3} ) - (\frac{x* 0^{2}}{2} +\frac{x * 0^{3}}{3})} \, dx = 1$

$c\int\limits^3_0 {(\frac{x* 9}{2} +\frac{x * 27}{3} ) - (0 +0) \, dx = 1$

$c\int\limits^3_0 {(\frac{9x}{2} +\frac{27x}{3} ) \, dx = 1$

Add fraction

$c\int\limits^3_0 {(\frac{27x + 54x}{6}) \, dx = 1$

$c\int\limits^3_0 {\frac{81x}{6} \, dx = 1$

Rewrite;

$c\int\limits^3_0 (81x * \frac{1}{6}) \, dx = 1$

The $\frac{1}{6}$ is a constant, so it can be removed from the integral sign to give

$c * \frac{1}{6}\int\limits^3_0 (81x ) \, dx = 1$

$\frac{c}{6}\int\limits^3_0 (81x ) \, dx = 1$

Integrate with respect to x

$\frac{c}{6} * \frac{81x^{2}}{2} (0,3) = 1$

Substitute 0 and 3 for x

$\frac{c}{6} * \frac{81 * 3^{2} - 81 * 0^{2}}{2} = 1$

$\frac{c}{6} * \frac{81 * 9 - 0}{2} = 1$

$\frac{c}{6} * \frac{729}{2} = 1$

$\frac{729c}{12} = 1$

Multiply both sides by $\frac{12}{729}$

$c = \frac{12}{729}$

$c = 0.0165 (Approximately)$

8 0

3 years ago

75 miles in 3 hours ; 140 miles in 4 hours

weeeeeb [17]

Answer:

Step-by-step explanation:

75:3=25:1

140:4=45:1

5 0

3 years ago