Answer:
The coefficient of correlation=0.5
Step-by-step explanation:
We are given that
Covariance between the variable x and y=18
Variance of x=16
Variance of y=81
We have to find the coefficient of correlation
We know that
Coefficient of correlation
![r=\frac{covariance(x,y)}{\sqrt{variance(x)}\times \sqrt{variance(y)}}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bcovariance%28x%2Cy%29%7D%7B%5Csqrt%7Bvariance%28x%29%7D%5Ctimes%20%5Csqrt%7Bvariance%28y%29%7D%7D)
Using the formula
![r=\frac{18}{\sqrt{16}\times \sqrt{81}}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B18%7D%7B%5Csqrt%7B16%7D%5Ctimes%20%5Csqrt%7B81%7D%7D)
![r=\frac{18}{4\times 9}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B18%7D%7B4%5Ctimes%209%7D)
![r=0.5](https://tex.z-dn.net/?f=r%3D0.5)
Hence, the coefficient of correlation=0.5
29.74*60=1,784.4
Mercury will travel 1,784 miles in a minute.
Add the fractions 1/4 and 3/8
First find the LCD of 1/4 and 3/8. 8 is the LCD.
Turn 1/4 into 2/8.
Now add.
3/8+2/8=5/8
Hope this helps!