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3 years ago

What is the greatest common factor of 90 and 15

2 answers:

8 0

The greatest common factor is the highest number that divides exactly into two or more numbers.

15: 1, 3, 5, 15 

90: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90 

The GCF for 15 and 90 is 15.

Leviafan [203]3 years ago

7 0

$90: \ 30, \ 6 
 \\ 15: \ 5, \ 1
 \\ 3 \ x \ 5 \ = \ 15
 \\ GCF: \ 15

$

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Certain tubes manufactured by a company have a mean lifetime of 800 hours and a standard deviation of 60 hours. Find the probabi

Anna71 [15]

Answer:

Step-by-step explanation:

given that certain tubes manufactured by a company have a mean lifetime of 800 hours and a standard deviation of 60 hours.

Sample size n =16

Std error of sample mean = $\frac{\sigma}{\sqrt{n} } \\= 15$

x bar follows N(800, 15)

the probability that a random sample of 16 tubes taken from the group will have a mean lifetime

(a) between 790 and 810 hours,

= $P(790$

(b) less than 785 hours

$=P(X$

, (c) more than 820 hours,

$=P(X>820)\\=p(Z>1.333)\\= 0.0913$

(d) between 770 and 830 hours

= $P(|Z|$

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

i need something for my assiemt How is an inequality different from an equation? Give a real-world scenario in which you would w

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An equation is a mathematical statement that shows the equal value of two expressions while an inequality is a mathematical statement that shows that an expression is lesser than or more than the other. "An 18-wheel truck stops at a weigh station before passing over a bridge. The weight limit on the bridge is 65,000 pounds. The cab (front) of the truck weighs 20,000 pounds, and the trailer (back) of the truck weighs 12,000 pounds when empty. In pounds, how much cargo can the truck carry and still be allowed to cross the bridge?" does this help?

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3 years ago

Answer these 2 questions please

Whitepunk [10]

Hi there!

Question 1:

For this, we are taking away 1/4 yards of spring from 7/8 yards. This is essentially just subtracting 1/4 from 7/8. This then gives us the equation:

$\frac{7}{8}-\frac{1}{4}$

Now, to subtract these, we want to make it so the denominators are the same, or the numbers on the lower half are the same. (One way to explain why this is true is: $\frac{a}{b}-\frac{c}{b}=a\frac{1}{b}-c\frac{1}{b}=(a-c)\frac{1}{b}=\frac{a-c}{b}$ ). Now, to make it so the denominators are the same, we can multiply the second fraction, 1/4, by 2/2 as 2/2 is essentially 1, and multiplying by 1 will get the same result, just with a denominator switched in this case. Doing this, we get:

$\frac{7}{8}-\frac{1}{4}\cdot\frac{2}{2}$

$\frac{7}{8}-\frac{2}{8}$

Now, subtracting the numerators, we get:

$\frac{5}{8}$ yards of string will remain.

Question 2:

For this, we are combining these two thicknesses, and thus we add 1/4 to 7/12. This gives us the equation:

$\frac{1}{4}+\frac{7}{12}$

Now, we again want to make it so the denominators are the same. (Here's a similar proof but for addition this time: $\frac{a}{b}+\frac{c}{b}=a\frac{1}{b}+c\frac{1}{b}=(a+c)\frac{1}{b}=\frac{a+c}{b}$ ). Now, to make the denominators the same, we can multiply the first fraction, 1/4, by 3/3 (also equivalent to 1). Doing this, we get:

$\frac{1}{4}\cdot\frac{3}{3}+\frac{7}{12}$

$\frac{3}{12}+\frac{7}{12}$

$\frac{10}{12}$ , which is equivalent to (dividing both the top and the bottom by 2) $\frac{5}{6}$ inches.

Hope this helps!

8 0

3 years ago