3 years ago

For f(x)=4x+1 and g(x)=(x^2)-5, find (f-g)(x).

1 answer:

8 0

$f(x)=4x+1,\ g(x)=x^2-5\\\\(f-g)(x)=f(x)-g(x)\\\\(f-g)(x)=(4x+1)-(x^2-5)=4x+1-x^2-(-5)\\\\=4x+1-x+5=-x^2+4x+(1+5)\\\\=\boxed{(f-g)(x)=-x^2+4x+6}$

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