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2 years ago

15

Every year from 2010 to 2013, the low

1 answer:

nasty-shy [4]2 years ago

7 0

Step-by-step explanation:

you need a accultur in order to do this the easy way enless you wanna do y2 minus y1 over x2 minis x1

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ashly lives 3/4 miles from her school. She walked 1/2 of the way from her home draw a model and work. and you have to do 3/4 x 1

Nezavi [6.7K]

Answer:

3/8?

Step-by-step explanation:

4 0

1 year ago

Read 2 more answers

The daily average temperature in Santiago, Chile, varies over time in a periodic way that can be modeled approximately by a trig

natali 33 [55]

Answer:

a) the trigonometric function is;

$y = 7.5 sin ( \frac{2 \pi}{365}t + \frac{337 \pi}{730})+ 21.5$

b) $y = 28.36^0 \ C$ ( to two decimal places)

Step-by-step explanation:

This data can be represented by the sinusoidal function of the form :

$\mathbf{y = A sin (Bt -C)+D}$

where A = amplitude and which can be determined via the formula:

$A = \dfrac{largest \ temperature - lowest \ temperature}{2}$

$A = \dfrac{29-14}{2}$

$A = \dfrac{15}{2}$

A = 7.5° C

where B = the frequency;

Since the data covers a period of 3 days ; then $\dfrac{2 \pi}{B } =365$

$B = \dfrac{2 \pi}{365}$ ( where 365 is the time period )

The vertical shift is found by the equation D;

D = $\frac{largest \ temperature + lowest \ temperature}{2}$

D = $\frac{29+14}{2}$

D = 21.5

Replacing the values of A ; B and D into the above sinusoidal function; we have :

$y = 7.5 sin (\frac{2 \pi}{365}t -C) + 21.5$

From the question; when it is 7th of the year ( i.e January 7);

t = 7 and the temperature (y) = 29° C

replacing that too into the above equation; we have:

$29= 7.5 sin (\frac{2 \pi}{365}*7 -C) + 21.5$

$29= 7.5 sin (\frac{14 \pi}{365} -C) + 21.5$

$\frac{29-21.5}{7.5}= sin (\frac{14 \pi}{365} -C)$

$1= sin (\frac{14 \pi}{365} -C)$

$sin^{-1}(1)= (\frac{14 \pi}{365} -C)$

$\frac{\pi}{2}= (\frac{14 \pi}{365} -C)$

$C= (\frac{14 \pi}{365} -\frac{\pi}{2})$

$C= (\frac{28 \pi- 365 \pi}{730} )$

$C= \frac{-337 \pi}{730}$

Thus; the trigonometric function is;

$y = 7.5 sin ( \frac{2 \pi}{365}t + \frac{337 \pi}{730})+ 21.5$

Similarly; to determine the temperature o Jan 31; i.e when t= 31 ; we have :

$y = 7.5 sin ( \frac{2 \pi}{365}*31+ \frac{337 \pi}{730})+ 21.5$

$y = 7.5 sin ( \frac{62 \pi}{365}+ \frac{337 \pi}{730})+ 21.5$

$y = 7.5 sin ( \frac{124 \pi+ 337 \pi }{730})+ 21.5$

$y = 7.5 sin ( \frac{461 \pi }{730})+ 21.5$

$y = 7.5 *( 0.915)+ 21.5$

$y = 6.8689+ 21.5$

$y = 28.36^0 \ C$ ( to two decimal places)

7 0

2 years ago

Read 2 more answers

What is the midpoint

antoniya [11.8K]

<u>Answer:</u>

(0.5, -0.5)

<u>Step-by-step explanation:</u>

We are given a line segment on the graph with two known points (ending points) and we are to find its mid point.

We know the formula for the mid point:

$Midpoint = ( \frac {x_1 + x_2} {2} ,\frac {y_1 + y_2} {2} )$

Substituting the coordinates of the given points in the above formula:

Mid point = $(\frac {5 + (-4) } {2} , \frac { 6 + (-7)} {2} )$ = (0.5, -0.5)

8 0

3 years ago

Read 2 more answers

PLEASE CAN SOMEONE HELP ASAP!!!!!!!!<br> DUE BY 11:59 OMGGG

Vaselesa [24]

Answer:

A, C, F

Step-by-step explanation:

JK is proportional to PQ, so that would be 8/x. Then, JL is proportional to PR, which would be 10/5. So, the answer is: 8/x = 10/5

Then, C would also be correct as KL is proportional to QR, and JK is proportional to PQ.

Finally, F is correct as JK to KL is proportional to PQ to QR, as JK is proportional to PQ, and KL is proportional to QR.

5 0

2 years ago

Pleaaaase help meee!

drek231 [11]

You need a circle graph

8 0

3 years ago